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3 years ago

Let f(x) = x2 − 81. Find f−1(x).

1 answer:

3 0

F(x) = x² - 81

Finding f⁻¹(x) the inverse function

Let y = f(x) and solve for x.

y = x² - 81

y + 81 = x²

x² = y + 81

x = √(y + 81)

Recall f(x) = y, that means x = f⁻¹(y)

x = √(y + 81)

f⁻¹(y) = √(y + 81)

Therefore f⁻¹(x) = √(x + 81)

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A random sample of n = 16 professors from a university has been selected; salaries have been plotted on the following Q-Q plot.

Semenov [28]

Answer:

The objective of the confidence interval is to give a range in which the real mean of the population is placed, with a degree of confidence given by the level of significance.

The conclusion we can make is that there is 95% of probability that the mean of the population (professor's average salary) is within $99,881 and $171,172.

Step-by-step explanation:

This is a case in which, from a sample os size n=16, a confidence interval is constructed.

The objective of the confidence interval is to give a range in which the real mean of the population is placed, with a degree of confidence given by the level of significance. In this case, the probability that the real mean is within the interval is 95%.

5 0

3 years ago

How o I get the awnser to 9s+3=57 I need help asap im in 8th grade

PIT_PIT [208]

First subtract 3 from both sides of the equal sign.
9s + 3 = 57
- 3 -3
9s = 54

Then divide both sides by 9.
9s = 54
/9 /9
s = 6

You can check it by plugging it back into the equation.
9s + 3 = 57
9 * 6 + 3= 57
54 + 3 = 37
57 = 57
Yep! It's correct! :)

Hope that helped. Algebra can be tricky sometimes I know but it's really just balancing equations.

3 0

3 years ago

Question is in the picture, please help me out!!

Grace [21]

The arithmetic sequences are as follow:

<h3>What is Arithmetic Sequence?</h3>

An arithmetic sequence in algebra is a sequence of numbers where the difference between every two consecutive terms is the same.

1) t(n) = 5n + 4

t(1) = 9, t(2) = 14, t(3) = 19

So,

9,14,19,...

d= 14-9 = 5

d= 19-14 =5

Hence, it is an AP

2) 1, 2, 4, 8 , 16

Hence, it is not an AP

3) 3, 6, 9 ,...

It is an AP

4)It is given that it is an AP

5) tn = 2*3^n

t1= 6, t2= 18, t3= 54

So, 6, 18, 54,...

Hence, it is not an AP

6) 3 , 1, 1/3,...

It is not an AP

7) t(n+1)= 6*t(n)

t(1) = -1

t(2)=-6

t(3)= -36

Hence, it is not an AP

8) -3, 1, 5, 9

Hence, it is an AP.

9) 1, 4, 9,...

Hence, it not an AP

10) 2,1,0,1,2,...

It is not an AP

11) t(n)= -2n-5

t(1)= -7, t(2)= -9, t(3)= -11

Hence, it is an AP

12) tn= (1/2)^n

t1= 1/2, t2= 1/4, t3= 1/8

It is not an AP

Learn more about AP here:

brainly.com/question/24873057

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