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3 years ago

What is - √61 to the nearest integer and nearest tenth?

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

3 0

The nearest integer would be 8.

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Find slope of a straight line if both intercept are equal

Juli2301 [7.4K]

Answer:

-1

Step-by-step explanation:

Let the points be (0, a) and (a, 0) (As it mentions the intercepts are equal)

==============================================================

Applying slope formula :

⇒ m = 0 - a / a - 0

⇒ m = -a/a

⇒ m = -1

6 0

2 years ago

What is the answer? Expand and simplify 6(2x-3)-2(2x+1)

vitfil [10]

Answer:

8x-20

Step-by-step explanation:

Distribute:

=(6)(2x)+(6)(−3)+(−2)(2x)+(−2)(1)

=12x+−18+−4x+−2

Combine Like Terms:

=12x+−18+−4x+−2

=(12x+−4x)+(−18+−2)

=8x+−20

Answer:

=8x−20

7 0

3 years ago

What is the answer of 3x?

Fiesta28 [93]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Use the quadratic formula to solve x2 + 2x - 120 = 0. Think about what other method could also be used to solve this equation. a

pshichka [43]

Answer:

x = 10 , -12

Step-by-step explanation:

Solution:-

- The given quadratic equation is to be solved using the quadratic formula. The general form of a quadratic equation is:

$ax^2 + bx + c =0$

Where, [ a , b and c are constants ]

- The quadratic formula is given as:

$x = \frac{-b+/-\sqrt{b^2 - 4*a*c} }{2a}$

- The given equation is:

$x^2 + 2x - 120 = 0$

Where, a = 1 , b = 2 , c = -120

- Solve using quadratic formula:

$x = \frac{-2+/-\sqrt{2^2 - 4*1*(-120)} }{2*1}\\\\x = \frac{-2+/-\sqrt{4 + 480} }{2}\\\\x = \frac{-2+/-(22) }{2}\\\\\\x = 10 , -12$

7 0

3 years ago

An arithmetic sequence has this recursive formula: (a^1 =8, a^n= a^n-1 -6

eduard

Answer:

$a_n = 8 + (n - 1) (-6)$

Step-by-step explanation:

Given

$a_1 = 8$

Recursive: $a_{n} = a_{n-1} - 6$

Required

Determine the formula

Substitute 2 for n to determine $a_2$

$a_{2} = a_{2-1} - 6$

$a_{2} = a_{1} - 6$

Substitute $a_1 = 8$

$a_2 = 8 - 6$

$a_2 = 2$

Next is to determine the common difference, d;

$d = a_2 - a_1$

$d = 2 - 8$

$d = -6$

The nth term of an arithmetic sequence is calculated as

$a_n = a_1 + (n - 1)d$

Substitute $a_1 = 8$ and $d = -6$

$a_n = a_1 + (n - 1)d$

$a_n = 8 + (n - 1) (-6)$

Hence, the nth term of the sequence can be calculated using $a_n = 8 + (n - 1) (-6)$

3 0

3 years ago