Given
- f(n) values for n=1,2,3,4
- possible candidates for the function
Solution:
Method: Evaluate some of the values, for each function. A function with ANY value not matching the given f(n) values will be rejected.
N=1, f(n)=4
f(1)=4-3(1-1)=4
f(1)=4+3^(1+1)=4+3^2=4+9=13 ≠ 4 [rejected]
f(1)=4(3^(n-1))=4(3^0)=4
f(1)=3(4^(n-1))=3(4^0)=3*1=3 [rejected]
N=2, f(n)=12
f(1)=4-3(2-1)=4-3(1)=1 ≠ 12 [rejected]
[rejected]
f(1)=4(3^(2-1)=4*3^1=4*3=12
[rejected]
Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36 [Good]
[rejected]
Solution: f(n)=4(3^(n-1))
Well, since you have two variables in one equation, you would have to have at least one other equation to solve this problem. Their isn't enough information to solve this alone, sorry :/
Let x = the number of alternative schools.
Therefore, 2x - 4 = 48.
2x -4 +4 = 48 + 4
2x = 52
x = 26
Therefore, there are 26 alternative schools(You could check this answer by substituting x=26 into the equation above.).
Answer: the equation would be 5n=1,500
Step-by-step explanation:
5 dollars per N (student) they need to make 1,500 so you need to find n
( to find N do 1,500 divided by 5 = 300
