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tankabanditka [31]
3 years ago
13

SOMEONE PLS HELP I DONT WANT TO FAIL THIS TEST

Mathematics
1 answer:
ryzh [129]3 years ago
7 0

Answer:

Internet

Step-by-step explanation:

If this is on Edginuity, highlight the whole question and picture, but not the answer options, and enter it into your search bar. that is what I do and it works

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A graduate student conducted a study of field mice in rural Kansas. The student obtained a sample of 100 field mice and recorded
BigorU [14]

Answer is in the photo. I can only upload it to a file hosting service. link below!

tinyurl.com/wtjfavyw

6 0
3 years ago
A can of peas weighs 10 oz. Explain how you would make a graph to model the total weight of peas in terms of the number of cans
Vika [28.1K]
Ur x axis will be the number of cans and ur y axis will be the weight in oz

u will label ur x axis( the number of cans) in intervals of 1......from 0 to 4
u will label ur y axis (the weight) in intervals of 10....from 0 to 40

ur equation would be : y = 10x
points on this line are : (0,0), (1,10), (2,20), (3,30), (4,40)
3 0
3 years ago
Read 2 more answers
X+Y-Z=19<br> 2X-3Y+Z=13<br> 3X-5Y-6Z=-15
lawyer [7]

A suitable graphing caculator gives the result

X = 15 25/39

Y = 7 6/13

Z = 4 4/39

_____

If you want to solve this by hand, you can add 3 times the first equation to the second to get

... 5X -2Z = 70

and 5 times the first equation to the third to get

... 8X -11Z = 80

Then Cramer's Rule tells you the solutions for X and Z are

... X = (-160+770)/(-16+55) = 610/39

... Z = (560 -400)/39 = 160/39

From there, you can substitute into any of the equations to find Y. The first one might be most convenient.

... Y = 19 -X +Z = 19 -(15 25/39) +(4 4/39) = 8 -21/39 = 7 6/13

7 0
3 years ago
Given matrix A below, and that A = B, find the value of the elements in B. A = 9 −2 3 2 17 0 3 22 8 b11 = b12 = b13 = b21 = b22
GuDViN [60]

Answer:

b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8

Step-by-step explanation:

Consider the given matrix

A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]

Let matrix B is

B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

It is given that

A=B

\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

On comparing corresponding elements of both matrices, we get

b_{11}=9,b_{12}=-2,b_{13}=3

b_{21}=2,b_{22}=17,b_{23}=0

b_{31}=3,b_{32}=22,b_{33}=8

Therefore, the required values are b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8.

3 0
3 years ago
Read 2 more answers
A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2
alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

dθ/dt = (1/√[20² - 16²]) 2 ft/s

dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s

8 0
4 years ago
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