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Andrei [34K]
3 years ago
9

What number could you put into the blank to make the value of this expression 6.93? 6.93×. 4.21+3.56

Mathematics
1 answer:
Sever21 [200]3 years ago
8 0
You can try - 7.43126.
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65.4 x 2.3 SHOW WORK!!! plz
bagirrra123 [75]

Answer:

Hello so.

65.4 x 2.3 = 150.42

Step-by-step explanation:

The Images I have attached show the work.

6 0
2 years ago
What expression is equivalent to the area of metal sheet required to make this square-shaped traffic sign?
AveGali [126]

Answer: \text{Area of the square shaped traffic sign }=16x^2+9+24x

Step-by-step explanation:

Given: The side of the square shaped traffic sign = 4x+3

We know that the area of square is given by:-

Area= side^2

Therefore, the area of the side of the square shaped field is given by:-

Area=(4x+3)^2

We know that , (a+b)^2=a^2+b^2+2ab

Therefore,

(4x+3)^2=(4x)^2+(3)^2+2(4x)(3)\\=16x^2+9+24x

Hence, \text{Area of the square shaped traffic sign }=16x^2+9+24x

3 0
3 years ago
Read 2 more answers
In a long-jump competition, Connor jumped 160 centimetres.
xeze [42]

Answer:

290 cm

Step-by-step explanation:

There are 100 centimeters in a meter so 1.3m*100 is 130cm

130+160cm is 290cm.

6 0
2 years ago
Simplify the expression below and write it as a single logarithm:
OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

<u>Solution:</u>

Given, expression is 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

Rearranging the terms we get,

\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)

\text { since a } \times \log b=\log \left(b^{a}\right)

\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)

\text { We know that } \log a \times \log b=\log a b

\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.

\text { We know that } \log a-\log b=\log \frac{a}{b}

\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

Hence, the simplified form \rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

4 0
3 years ago
Read 2 more answers
1 1/2 x ^ 3 * 8/15 * the power of 2
Mnenie [13.5K]

Your drawing was much more helpful and informative than your statements in words and symbols.

I see that you want to evaluate (3/2)^2 times (8/15)^2.

You could combine these two expressions into one, as follows:

3*8

( ----------- )^2

2*15

This, in turn, can be simplified by reduction:


( 4/5 )^2. Expanded, this result gives us 16/25.


Next problem

----------------------------

( 9/4 )^4 * ( 4/3 )^3

9^4 4^3

First, focus on ( ------- ) * ( ----------- )

4^4 3^3

Now reduce 4^3 / 4^4: The end result is 1/4.

Reduce 9^4 / 3^3. To do this, rewrite that 9 as (3^2), resulting in:

3^8 / 3^3. The end result is 3^5.

Putting this expression back together, we get 3^5 / 4 (answer)

4 0
3 years ago
Read 2 more answers
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