Answer:
72/96
Step-by-step explanation:
I think the answer's 7/8. If you convert 1/4 to 2/8 and add them together, you add 5/8 and 2/8 to get 7/8.
This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get
![x^2 + 11x - 4 = 0](https://tex.z-dn.net/?f=%20x%5E2%20%2B%2011x%20-%204%20%3D%200%20)
i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:
![x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}](https://tex.z-dn.net/?f=%20x_%7B1%2C2%7D%20%3D%20%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2%7D%20)
where
is a compact way to indicate both solutions
and
, while
are the coefficients of the quadratic equation, i.e. we consider the polynomial
.
So, in your case, we have ![a=1,\ \ b=11,\ \ c=-4](https://tex.z-dn.net/?f=%20a%3D1%2C%5C%20%5C%20b%3D11%2C%5C%20%5C%20c%3D-4%20)
Plug those values into the formula to get
![x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}](https://tex.z-dn.net/?f=%20x_%7B1%2C2%7D%20%3D%20%5Cfrac%7B-11%5Cpm%5Csqrt%7B121%2B16%7D%7D%7B2%7D%20%3D%20%5Cfrac%7B-11%5Cpm%5Csqrt%7B137%7D%7D%7B2%7D%20)
So, the two solutions are
![x_1 = \frac{-11+\sqrt{137}}{2}](https://tex.z-dn.net/?f=%20x_1%20%3D%20%5Cfrac%7B-11%2B%5Csqrt%7B137%7D%7D%7B2%7D%20)
![x_2 = \frac{-11-\sqrt{137}}{2}](https://tex.z-dn.net/?f=%20x_2%20%3D%20%5Cfrac%7B-11-%5Csqrt%7B137%7D%7D%7B2%7D%20)
Answer:
B (4,2)
Step-by-step explanation:
This coordinate pair would make the relation not a function because there would be two X values that are the same.
Answer: They can order from 0 to 449 bars, but no more.
Step-by-step explanation:
Given: The school band is ordering health bars to sell for a fundraiser. The company that sells the bars charges $0.40 per bar plus $20.00 for shipping regardless of the size of the order. The band must spend less than $200.00 on bars for the fundraiser.
The inequality below relates x, the number of bars that could be ordered, with the shipping costs and their spending requirements.
![0.40x+20](https://tex.z-dn.net/?f=0.40x%2B20%3C200)
To solve for x, subtract 20 on both sides, we get
![0.40x](https://tex.z-dn.net/?f=0.40x%3C108)
Divide 0.40 on both sides, we get
......... → the number of bars that could be ordered, with the shipping costs and their spending requirements must less than 450.
Thus, they can order from 0 to 449 bars, but no more.