Factor by grouping. a2 + ab – 56b2

2 answers:

8 0

A^2 + ab - 56b^2

Factor by grouping is typically done when you have 4 terms not 3.
This is a trinomial that is factorable as is.
If it has to be done by grouping I can do that also. Let me know.

What are the factors of -56 that add up to 1?
8 * (-7) = -56
8 + (-7) = 1

(a + 8b)(a - 7b)

goblinko [34]3 years ago

7 0

a^2 + ab -56b^2
= a^2 +8ab -7ab -56b^2
= a (a+8b) -7b ( a+ 8b)
= (a-7b)(a+8b).

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Can someone help me plz I'm confused

muminat

9.

2x+3+x+9 = 180 => 3x = 168 => x = 56;
m(<ABD) = 2*56 + 3 = 115.

4 0

3 years ago

Zayed is helping his classmates get ready for their math test by making them identical packages of pencils and calculators. He h

zmey [24]

Answer:

3 pencils

Step-by-step explanation:

We are given Zayed is helping his classmates get ready for their math test by making them identical packages of pencils and calculators.

Number of pencils=72

Number of calculators=24

If Zayed creates the greatest number of identical packages

Then , we find GCF of 72 and 24

$72=2\times 2\times 2\times 3\times 3$

$24=2\times 2\times 2\times 3$

GCF= $2\times 2\times 2\times 3$

Hence, Zayed creates 24 packages.

Number of pencils in each package= $\frac{72}{24}=3$

Hence, 3 pencils and one calculator will be in each package .

4 0

3 years ago

Read 2 more answers

Find the function value of cos^2 (7pi/8)

Kamila [148]

$\cos^2\dfrac{7\pi}8=\dfrac12\left(1+\cos\dfrac{7\pi}4\right)$
$=\dfrac12+\dfrac12\cos\left(-\dfrac\pi4\right)$
$=\dfrac12+\dfrac12\cos\dfrac\pi4$
$=\dfrac12+\dfrac1{2\sqrt2}$
$=\dfrac{\sqrt2+1}{2\sqrt2}$
$=\dfrac{2+\sqrt2}4$