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Ivenika [448]
3 years ago
8

2+266666662724683745946198753278313=

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
6 0

Answer:

2.6666666e+32

Step-by-step explanation:

1.add

2.multiply

3. you have your answer

You might be interested in
5n+5=45 what does n =
joja [24]
5n+5=45
Subtract 5 from both sides
5n=40
Divide both sides by 5
n=8

I hope this helps
4 0
3 years ago
Anyone help me? Solve this problem ​
strojnjashka [21]

the answer is in the picture I mentioned as the answer ok ◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉◉‿◉

7 0
3 years ago
An automobile manufacturer finds that 1 in every 2500 automobiles produced has a particular manufacturing defect. ​(a) Use a bin
Advocard [28]

Answer:

a) 0.1558 = 15.58% probability of finding 4 cars with the defect in a random sample of 7000 cars.

b) 0.1557 = 15.57% probability of finding 4 cars with the defect in a random sample of 7000 cars. These probabilities are very close, which means that the approximation works.

Step-by-step explanation:

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

To use the Poisson approximation for the binomial, we have that:

\mu = np

1 in every 2500 automobiles produced has a particular manufacturing defect.

This means that p = \frac{1}{2500} = 0.0004

a) Use a binomial distribution to find the probability of finding 4 cars with the defect in a random sample of 7000 cars.

This is P(X = 4) when n = 7000. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{7000,4}.(0.0004)^{4}.(0.9996)^{6996} = 0.1558

0.1558 = 15.58% probability of finding 4 cars with the defect in a random sample of 7000 cars.

(b) The Poisson distribution can be used to approximate the binomial distribution for large values of n and small values of p.

Using the approximation:

\mu = np = 7000*0.0004 = 2.8. So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-2.8}*(2.8)^{4}}{(4)!} = 0.1557

0.1557 = 15.57% probability of finding 4 cars with the defect in a random sample of 7000 cars. These probabilities are very close, which means that the approximation works.

6 0
3 years ago
PLEASE I NEED HELP WITH THIS SO I CAN PASS
torisob [31]
Guess ur not passing today
5 0
2 years ago
Read 2 more answers
Nina Milling assembles transistor radios. she is paid $0.54 for each radio assembled during a regular work week, $0.62 for each
Inessa [10]

Answer:

I would need to know the number of radios she made each day.

Step-by-step explanation:

lets say she assembled 2 radios a day, which means we would do 0.54 x 2 (that would be 1.08) and then times it by 6 ***not incuding sunday***

you would get $6.48

then for sunday we would do 0.62 x 2 (that would be 1.24) .

now we add 6.48 and 1.24 to get $7.72 a week.

6 0
2 years ago
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