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3 years ago

QUESTION 69

Mathematics

1 answer:

bazaltina [42]3 years ago

8 0

The line is parallel to x-axis

the correct answer -

y = –4

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I need help as fast as possible

aivan3 [116]

Answer:

36°

Step-by-step explanation:

Given,

Measurement of <3 = 2x+8

Measurement of <4 = 6x+12

Since both are supplementary,

Therefore,

<3 + <4. = 180° [linear pair]

=> 2x + 8 + 6x + 12 = 180

=> 2x + 6x + 8 + 12 = 180

=> 8x + 20 = 180

=> 8x = 180 - 20 = 160

$= > x = \frac{160}{8}$

=> x = 20

Now as we have got the value of x,

According to the question measurement of <4 is,

<4 = 6×4 + 12 = 24 + 12 = 36° (Ans)

4 0

2 years ago

Y = x – 6

zhenek [66]

-4-6= -10
-10 = Y
-4 = X
Therefore the answer is (-4,-10) which isn’t on the options

8 0

2 years ago

Find the unknown sizes of angles:

almond37 [142]

X=92

X+Y=180

Y=180-92

Y=88

Z=Y=88

6 0

2 years ago

Read 2 more answers

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

Equation Solving

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

2 years ago

All triangles have at least 2 acute angles

katrin2010 [14]

Correct
a right triangle will have 1 right angle and 2 acute angles.
an obtuse triangle will have 1 obtuse triangle and 2 acute angles.

6 0

2 years ago