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iVinArrow [24]
3 years ago
12

When a number is decreased by 3.5%, the result is 91 what is the original number to the nearest tenth

Mathematics
2 answers:
sdas [7]3 years ago
4 0

Answer:

87.8

Step-by-step explanation:

So you have to multiply 91 times 3.5 which equals 318.5

                      91 × 3.5 = 318.5

Then divide 318.5 by 100 which equals 3.185

                      318.5 ÷ 100 = 3.185

Next subtract 91 by 3.185 which equals 87.815

                      91 - 3.185 = 87.815

Last Round 87.815 to 87.8

                       87.8 should be the answer

Hope this helps

rodikova [14]3 years ago
3 0

Answer:

The number is 94.3 (to the nearest tenth)

Step-by-step explanation:

Let the number =x

When x is decreased by 3.5%, we have:

(100% of x)-(3.5% of x)=(100-3.5)% of x =96.5% of x

When a number is decreased by 3.5%, the result is 91.

Therefore:

96.5% of x = 91

Converting percentage to decimal: 96.5%=0.965

0.965x = 91

Divide both sides by 0.965

x=94.3

The number is 94.3 (to the nearest tenth)

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Measure of angle TRV?
Helga [31]

Answer:

130 degrees

Step-by-step explanation:

We know (x-10)+(2x+10) is 180 degrees.

So first we need to find x. (x-10)+(2x+10)=3x

3x=180

x=60

Angle TRV is 2x+10.

If we input 60 in the place of x, it is 2(60)+10=120+10=130.

The answer is 130 degrees.

6 0
2 years ago
The Sun is roughly 10^2 times as wide as the Earth. The Star KW Sagittarii is roughly 10^5 times as wide as the Earth. About how
Studentka2010 [4]

Answer:

1000 times

Step-by-step explanation:

Given:

The Sun is roughly 10^2 times as wide as the Earth.

The Star KW Sagittarii is roughly 10^5 times as wide as the Earth.

Question asked:

About how many times as wide as the Sun is KW Sagittarii?

Solution:

Let the width of the earth =  x

As the Sun is roughly 10^2 times as wide as the Earth, hence the width of the sun = x\times10^{2}

And as the Star KW Sagittarii is roughly 10^5 times as wide as the Earth, hence the width of the Star = x\times10^{5}

Now, to find that how many times width of the Star  KW Sagittarii is as respect to the width of the Sun, we will simply divide:

Width of the Star  KW Sagittarii =  x\times10^{5}

Width of the Sun = x\times10^{2}

\frac{x\times10^{5} }{x\times10^{2} }

x canceled by x

\frac{10^{5} }{10^{2} } =10^{5-2} =10^{3} =10\times\ 10\times10=1000

Therefore, Star  KW Sagittarii is 1000 times wider than Sun.

<em>First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.</em>

<em />

4 0
3 years ago
10+2r=8 need the answer now
natulia [17]

Simplifying

10 = 2r + -8

Reorder the terms:

10 = -8 + 2r

Solving

10 = -8 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.

10 + -2r = -8 + 2r + -2r

Combine like terms: 2r + -2r = 0

10 + -2r = -8 + 0

10 + -2r = -8

Add '-10' to each side of the equation.

10 + -10 + -2r = -8 + -10

Combine like terms: 10 + -10 = 0

0 + -2r = -8 + -10

-2r = -8 + -10

Combine like terms: -8 + -10 = -18

-2r = -18

Divide each side by '-2'.

r = 9

Simplifying

r = 9

3 0
3 years ago
Read 2 more answers
Find an equation of the line passing through the point ( - 12,
kotegsom [21]
Just ignore that bot. The actual answer would be y = 1/4X - 2!

4 0
3 years ago
IM GIVEING ALL MY POINTS AWAY BECAUSE I NEED THIS DONE
iogann1982 [59]
Ight bet I’ll see what I can do
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3 years ago
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