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2 years ago

Geometry: complete this proof (ASAP! It’s urgent)

Mathematics

1 answer:

dexar [7]2 years ago

8 0

Answer:

1. <1 ~= <4 (Given)

2. <2 is supplementary to <1; <3 is supplementary to <4 (Because <1 & <2, <3 and <4 form linear pairs, they are supplementary by the linear pair postulate.)

3. <2 ~= <3 (By the definition of supplementary angles, m<1 + m<2 = 180 and m<3 + m<4 = 180. By definition of congruent angles, m<1 = m<4, therefore m<2 = m<3 by substitution property of equality.)

4. AB ~= BC (Converse of Isosceles Triangles Theorem)

5. Triangle ABC is isosceles (Definition of Isosceles Triangles)

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Answer:

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3 years ago

The ratio of the perimeter of two similar polygons is 5:7. The area of the smaller polygon is 30 sq. cm. Find the area of the la

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42sq

Step-by-step explanation:

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3 years ago

What is 14 subtracted from a number

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Answer:

x-14

Step-by-step explanation:

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2 years ago

Read 2 more answers

Factorize this expression completely <br>using (a-b)² formula<br>3a²- 36a + 108

Novosadov [1.4K]

Answer:

$3a^2 - 36a + 108 = (\sqrt{3}a - 6\sqrt{3} )^2$

Step-by-step explanation:

$3a^2 = (\sqrt{3} a)^2\\108 = 9 \times 4 \times 3= 3^2 \times 2^2 \times 3 = (3\times2 \sqrt{3} )^2 = (6\sqrt{3})^2$

$so, a = \sqrt{3} a \ , \ b = 6\sqrt{3} \\\\(a - b)^2 = a^2 -2ab + b^2\\\\-36a = -2ab\\\\-36a = -2 \times \sqrt{3} a \times 6\sqrt{3}$

Therefore ,

$3a^2 - 36a + 108 = (\sqrt{3}a )^2 - 2(\sqrt{3}a \times 6\sqrt{3} ) + (6\sqrt{3} )^2 = (\sqrt{3}a - 6\sqrt{3} )^2$

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3 years ago

Please answer this correctly

Sav [38]

Answer:

The range would not change

Step-by-step explanation:

If we replaced one of the 7s with a 5, we still have a 7. The range will be the highest number minus the lowest number (7 - 1 = 6). So the range would still not change because we still have another 7.

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3 years ago