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Zolol [24]
3 years ago
7

Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions:

Mathematics
1 answer:
MrMuchimi3 years ago
5 0
No, it is not in the solution area for the system.

The point only works in one of the inequalities. 

It doesn't work in the inequality: y > -1/2x+ 3

We can put it in to test it:

-7 > (-1/2)3 + 3
-7 > -1.5 + 3
-7 > 1.5  This is a false statement, therefore it is not part of the solution.
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If a line has a slope of -4 and a u intercept of 1, which of the following is it's graph?
3241004551 [841]
Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing
3 0
3 years ago
Whats 38240 divided by 4
inn [45]

Answer:

9560

Step-by-step explanation:

Use a calculator or do long division.

You can also divide by 2 twice.

38240/2 = 19120

19120/2 = 9560

Answer: 9560

4 0
1 year ago
Read 2 more answers
Using what you know about angles and triangles, what is the measure of angle 6?
zvonat [6]
∠4 = 90  (verticallyopposite)
∠2 = 68 (verticallyopposite)

∠6 = ∠2 + ∠4 (exterior angles = sum of opposite angles)

∠6 = 68 + 90 = 158°

Answer: 158°
7 0
2 years ago
Suppose that vehicles taking a particular freeway exit can turn right (R), turn left (L), or go straight (S). Consider observing
Basile [38]

Answer:

a)

A={RRR,SSS,LLL}

b)

B={RSL,SLR,LRS,RLS,SRL,LSR}

c)

C={RRL,RLR,LRR,RRS,SRR,RSR}

d)

D={RRL, RRS, RLR, RLL, RSR, RSS, LRR, LRL, LLR, LLS, LSL, LSS, SRR, SRS, SLL, SLS, SSR, SSL}

e)

D'={RRR, RLS, RSL, LRS, LLL, LSR, SRL, SLR, SSS}

Step-by-step explanation:

Sample space=S= {RRR, RRL, RRS, RLR, RLL, RLS, RSR, RSL, RSS, LRR, LRL, LRS, LLR, LLL, LLS, LSR, LSL, LSS, SRR, SRL, SRS, SLR, SLL, SLS, SSR, SSL, SSS}

a)

Let A be the event that all three vehicles go in same direction. It means that the all three vehicles go to right or left or straight. Thus, event A can be represented as

A={RRR,SSS,LLL}

b)

Let B be the event that all three vehicles go in different direction. It means that the three vehicles can go to

1. Right, Straight, Left

2. Straight, Left, Right

3. Left, Right, Straight

4. Right, Left, Straight

5. Straight, Right, Left

6.  Left, Straight, Right

Thus, event B can be represented as

B={RSL,SLR,LRS,RLS,SRL,LSR}

c)

Let C be the event that exactly two of three vehicles turn right. It means that the three vehicles can go to

1. Right, Right , Left

2. Right , Left, Right

3. Left, Right, Right

4. Right, Right , Straight

5. Straight, Right,Right

6.  Right , Straight, Right

Thus, event C can be represented as

C={RRL,RLR,LRR,RRS,SRR,RSR}

d)

Let D be the event that exactly two of three vehicles go in same direction. It means that the three vehicles can go to

1. Right,  Right, Left

2. Right, Right, Straight

3. Right, Left,  Right

4. Right, Left, Left

5. Right, Straight, Right

6. Right, Straight, Straight

7.  Left,  Right, Right

8. Left,  Right, Left

9. Left, Left, Right

10. Left, Left, Straight

11. Left, Straight, Left

12. Left, Straight, Straight

13. Straight, Right, Right

14. Straight, Right, Straight

15. Straight, Left, Left

16. Straight, Left, Straight

17. Straight, Straight, Right

18.Straight,Straight, Left

Thus, event D can be represented as

D={RRL, RRS, RLR, RLL, RSR, RSS, LRR, LRL, LLR, LLS, LSL, LSS, SRR, SRS, SLL, SLS, SSR, SSL}

e)

D'=S-D= {RRR, RRL, RRS, RLR, RLL, RLS, RSR, RSL, RSS, LRR, LRL, LRS, LLR, LLL, LLS, LSR, LSL, LSS, SRR, SRL, SRS, SLR, SLL, SLS, SSR, SSL, SSS} -{RRL, RRS, RLR, RLL, RSR, RSS, LRR, LRL, LLR, LLS, LSL, LSS, SRR, SRS, SLL, SLS, SSR, SSL}

D'={RRR, RLS, RSL, LRS, LLL, LSR, SRL, SLR, SSS}

8 0
3 years ago
3x+2y=3 Get y alone.
Kazeer [188]
3x + 2y = 3. subtract 3x from both sides, so you get 2y = -3x + 3 . then you divide by 2 to both sides , so you get y = -3/2x + 3/2 .
5 0
3 years ago
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