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Naily [24]
3 years ago
10

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi. The distances, m

easured in centimeters between cities on Allyson’s map are proportional to the real distances.
Which of the following could be the the distances on Allyson’s map?

Choose 3 answers

Bangalore to Mumbai: 116.5 cm
Mumbai to Delhi: 174 cm

Bangalore to Mumbai: 42.25
Mumbai to Delhi: 58 cm

Bangalore to Mumbai: 23.4 cm
Mumbai to Delhi: 29 cm

Bangalore to Mumbai: 16.9 cm
Mumbai to Delhi: 23.2 cm

Bangalore to Mumbai: 25.35 cm
Mumbai to Delhi: 34.8cm
Mathematics
2 answers:
Mazyrski [523]3 years ago
8 0

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi, then the ratio between these distances is

\dfrac{845}{1160}=\dfrac{169}{232}.

A. Bangalore to Mumbai: 116.5 cm;

Mumbai to Delhi: 174 cm

The ratio:

\dfrac{116.5}{174}=\dfrac{233}{348}\neq \dfrac{169}{232}

This option is false.

B. Bangalore to Mumbai: 42.25

Mumbai to Delhi: 58 cm

The ratio is

\dfrac{42.25}{58}=\dfrac{845}{1160}=\dfrac{169}{232}

This option is true.

C. Bangalore to Mumbai: 23.4 cm

Mumbai to Delhi: 29 cm

The ratio is

\dfrac{23.4}{29}=\dfrac{117}{145}\neq \dfrac{169}{232}

This option is false.

D. Bangalore to Mumbai: 16.9 cm

Mumbai to Delhi: 23.2 cm

The ratio is

\dfrac{16.9}{23.2}=\dfrac{169}{232}

This option is true.

E. Bangalore to Mumbai: 25.35 cm

Mumbai to Delhi: 34.8cm

The ratio is

\dfrac{25.35}{34.8}=\dfrac{507}{696}=\dfrac{169}{232}

This option is true.

Answer: correct options are B, D and E

Dahasolnce [82]3 years ago
4 0

Answer:

Step-by-step explanation:

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi, then the ratio between these distances is

A. Bangalore to Mumbai: 116.5 cm;

Mumbai to Delhi: 174 cm

The ratio:

This option is false.

B. Bangalore to Mumbai: 42.25

Mumbai to Delhi: 58 cm

The ratio is

This option is true.

C. Bangalore to Mumbai: 23.4 cm

Mumbai to Delhi: 29 cm

The ratio is

This option is false.

D. Bangalore to Mumbai: 16.9 cm

Mumbai to Delhi: 23.2 cm

The ratio is

This option is true.

E. Bangalore to Mumbai: 25.35 cm

Mumbai to Delhi: 34.8cm

The ratio is

This option is true.

Answer: correct options are B, D and E

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The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

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brainly.com/question/723406

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2 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0
3 years ago
Verify the identity. <br><br> sin (x+pi/2)=cos x
hram777 [196]
Given data 
<span>sin (x+pi/2)=cos x
</span>now using sin law
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now using above values
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as we know that
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now putting these values
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hence proved that

<span>sin (x+pi/2)=cos x</span>
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Answer:

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Step-by-step explanation:

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