Answer:
1. y = 4x - 27
2. y = -4x - 15
Step-by-step explanation:
If two lines are parallel, then they have the same slope. So, the slope of the line we are looking for needs to be 4. We can start by writing a point-slope equation:
y - y1 = m(x - x1)
We can substitute the values we have, the point we are using is (8, 5) because it needs to be on the line:
y - 5 = 4(x - 8)
We can distribute:
y - 5 = 4x - 32
y = 4x - 27
We are not given the slope-intercept form, so we must divide both sides by two to get it:
y = 1/4 x + 8
A perpendicular line has the slope that is the negative reciprocal of the one that is given. So, the slope of the line would be - 4. We can start by writing a point-slope equation:
y - y1 = m(x - x1)
We can substitute the values we have, the point we are using is (-5, 5) because it needs to be on the line:
y - 5 = -4(x + 5)
We can distribute:
y - 5 = -4x - 20
y = -4x - 15
Answer:
Angie plz get on soundtrap
Step-by-step explanation:
Answer:
D. C = 0.59x+ 275
Step-by-step explanation:
Hmmmm...... Are you a 6th grader? I remember doing these in 6th grade.
Answer:
1. 3
2. 2
Step-by-step explanation:
| |
x | + | 1 | | x^2 | + | 4 x | - | 2
x^3 | + | 5 x^2 | + | 2 x | + | 1
x^3 | + | x^2 | | | |
| | 4 x^2 | + | 2 x | |
| | 4 x^2 | + | 4 x | |
| | | | -2 x | + | 1
| | | | -2 x | - | 2
| | | | | | 3
__________________________________________
| |
x | - | 5 | | x^2 | - | x | + | 0
x^3 | - | 6 x^2 | + | 5 x | + | 2
x^3 | - | 5 x^2 | | | |
| | -x^2 | + | 5 x | |
| | -x^2 | + | 5 x | |
| | | | | | 2
| | | | | | 0
| | | | | | 2
