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3 years ago

Please help me:( been stuck

Mathematics

1 answer:

kati45 [8]3 years ago

5 0

Answer:

Can’t see it

Step-by-step explanation:

That’s tufffff

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-x + 4y when x = -4/5 and y = 1/3

Usimov [2.4K]

we have the expression

$-x+4y$

Evaluate for x=-4/5 and y=1/3

substitute the values of x and y in the given expression

$\begin{gathered} -(-\frac{4}{5})+4(\frac{1}{3}) \\ \frac{4}{5}+\frac{4}{3} \\ \frac{3\cdot4+5\cdot4}{15} \\ \frac{32}{15} \end{gathered}$

the answer is 32/15

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1 year ago

What 2 fingers should you use to properly check your pulse?

lesya692 [45]

Your middle finger and index/pointer.

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3 years ago

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What is the answer to 5t-26=18t

AlladinOne [14]

Answer:

t = -2

Step-by-step explanation:

5t - 26 = 18t

Add 26 to both sides:

5t - 26 + 26 = 18t + 26

Simplify:

5t = 18t + 26

Subtract 18t from both sides:

5t - 18t = 18t + 26 - 18t

Simplify:

-13t = 26

Divide both sides by -13:

-13t/-13 = 26/-13

Therefore:

t = -2

I hope this helps!

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3 years ago

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Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible

djverab [1.8K]

$\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
\\
\text{for any two natural numbers, their Least Common Multiple (LCM) is always}$

$\text{greater than their HCF.}\\
\\
\text{but here we can see that }LCM$

Hence there is no such natural numbers exist.

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3 years ago

A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe

Finger [1]

The probability is 0.1458.

The probability is given by:

$_{20}C_2(0.04)^2(1-0.04)^{20-2}
\\
\\=_{20}C_2(0.04)^2(0.96)^{18}=0.1458$

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3 years ago