The first one is 2x-3y/2
The second one is 1/x+2
The third one is (2x-5y)/(2x+5y)
The fourth one is x^2/z^2
To find it, evaluate it at the endpoints and the vertex
in form
f(x)=ax²+bx+c
the x value of the vertex is -b/2a
given
c(t)=1t²-10t+76
x value of vertex is -(-10)/1=10
evaluate c(0) and c(13) and c(10)
c(0)=76
c(13)=115
c(10)=76
it reached minimum in 2000 and 2010
porbably teacher wants 2010
the min value is $76
Answer:
x = -1
Step-by-step explanation:
5 less than a number is equivalent to 1 more than three times the number
number = x
x - 5 = 3x + 1
now im going to get the numbers and variable on different sides
x - 5 + 5 = x
3x + 1 - 3x = 1
x + 3x = 4x
1 - 5 = -4
4x = -4
lastly im going to divide each side by 4
4x / 4 = x
-4 / 4 = -1
x = -1
Answer:
4x-13 = 2x+9 ( i think it was exterior angle property i dont remember but its true)
so, solving that eq,
4x-2x = 9+13 (grouping variables and constants)
2x=22
x=11
also, 2x+9 and 3y+2 are on a transversal, and are supplementary angles (add up to 180°)
so, solving for x in 2x+9,
2(11)+9 = 22+9 = 31°
now, 31 + 3y+2 = 180
3y = 180 - 33
y = 147/3 = 49
(hoping you understood the calculations :)
Answer:
Step-by-step explanation:
- (x+y-z)²= 4xy
- (x+y-z)²- 4xy = 0
- (x+y-z)²-(2√x√y)² = 0
- (x+y-z-2√x√y)(x+y-z+2√x√y) =0
- [(√x-√y)²-z]*[(√x+√y)²-z]=0
- (√x-√y)²-z = 0 or (√x+√y)²-z = 0
We have : z^(1/2)= x^(1/2)+y^(1/2) ⇒ √z = √x + √y ⇒ z = (√x + √y)²
so (x+y-z)²= 4xy
