How do I do number 11

Which type of interest rate is not adjusted for different factors, including inflation?

Murrr4er [49]

Answer:

C: Nominial interest rate

Step-by-step explanation:

C

8 0

2 years ago

considering the leading term of the polynomial function. what is the end behavior of the graph? describe the end behavior and pr

mario62 [17]

The leading term of polynomial function is the the term contain highest degree so here in the given question leading term is $-3x^5$

and leading coefficient is the coefficient of the term with greatest exponent -3

RULES for End behaviour

we have following four cases

CASE1: Even degree and positive leading coefficient

$x\rightarrow -\infty$ $f(x)\rightarrow \infty$

$x\rightarrow \infty$ $f(x)\rightarrow \infty$

CASE2: Even degree and negative leading coefficient

$x\rightarrow -\infty$ $f(x)\rightarrow -\infty$

$x\rightarrow \infty$ $f(x)\rightarrow -\infty$

CASE3: Odd degree and positive leading coefficient

$x\rightarrow -\infty$ $f(x)\rightarrow -\infty$

$x\rightarrow \infty$ $f(x)\rightarrow \infty$

CASE4: Odd degree and negative leading coefficient

$x\rightarrow -\infty$ $x\rightarrow \infty$

$x\rightarrow \infty$ $f(x)\rightarrow -\infty$

Here in the given case we have odd degree and negative leading coefficient

$x\rightarrow -\infty$ $x\rightarrow -\infty$

$x\rightarrow \infty$ $f(x)\rightarrow -\infty$

3 0

2 years ago

What is x if y Is 5 <br> x^2 (2y +5)=240

UkoKoshka [18]

X^2(2y+5)=240
x^2(2(5)+5)=240
x^2+(10+5)=240
x^2+15=240
minus 15 both sides
x^2=225
sqrt both sides
x=15

6 0

3 years ago

Can someone help me with this question please

77julia77 [94]

Answer:

nca - gru is the correct answer

Step-by-step explanation:

6 0

2 years ago

Shawna invests $5,048 in a savings account with a fixed annual interest rate of 4% compounded 12 times per year. How long will i

Elena-2011 [213]

Answer:

5 years

Step-by-step explanation:

In the question we are given;

Amount invested or principal amount as $5048
Rate of interest as 4% compounded 12 times per year
Amount accrued as $6,163.59

We are required to determine the time taken for the money invested to accrue to the given amount;

Using compound interest formula;

$A=P(1+\frac{r}{100})^n$

where n is the interest period and r is the rate of interest, in this case, 4/12%(0.33%)

Therefore;

$6,163.59=5,048(1+\frac{0.333}{100})^n$

$1.221=(1+\frac{0.333}{100})^n$

$1.221=(1.0033)^n$

introducing logarithms on both sides;

$log1.221=log(1.0033)^n\\n=\frac{log1.221}{log1.0033} \\n=60.61$

But, 1 year = 12 interest periods

Therefore;

Number of years = 60.61 ÷ 12

= 5.0508

= 5 years

Therefore, it will take 5 years for the invested amount to accrue to $6163.59

3 0

3 years ago