Answer:
$1,800 was withdrawn because 18 * 100 = 1,800
<span> The coordinates of the focus are </span><span><span>(<span>h,k+<span>1/<span>4a</span></span></span>)</span><span>(<span>h,k+<span>1/<span>4a</span></span></span>)
y=1/38*x^2
here h=0,k=0 ,a=1/38
so if we put values to find focus
focus(0,0+1/4*1/38)=(0,9.5)
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Answer:
I think the change in volume is 26.8%
Step-by-step explanation:
I'm really sorry if I'm wrong
I think you're asking if it's possible to have a cube root, fifth root, 7th root, etc of a number as a solution to f(x). The answer is yes it's possible.
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Example:
f(x) = x^3 - 29
This function has one real-number root of ![x = \sqrt[3]{29}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B29%7D)
(cube root of 29) and the other two roots are complex or imaginary roots.
