PLEASE HELP!!! URGENT!!!

Mathematics

1 answer:

Kobotan [32]3 years ago

3 0

Answer:

They are both correct because there is more than one way to write a multivariable polynomial in standard form. Marcus has the exponents on the x variable in descending order from the highest degree to the lowest degree. Ariel has the exponents on the y variable in descending order from the highest degree to the lowest degree.

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Write the quadratic equation whose roots are six and -2 and who’s leading coefficient is 3 use the letter X to represent the var

Artist 52 [7]

Answer:

$3X^{2} - 12X - 36 = 0$

Step-by-step explanation:

6 and - 2 are the only two solutions to the required quadratic equation.

So, if the variable is represented by X then (X - 6) and (X + 2) will be the only two factors of the polynomial function.

Therefore, the equation is

(X - 6)(X + 2) = 0

⇒ $X^{2} - 4X - 12 = 0$

If the leading coefficient of the equation is 3 then we can write the equation as $3X^{2} - 12X - 36 = 0$ (Answer)

6 0

3 years ago

Which number gives you an irrational product when you multiply it by 2

soldi70 [24.7K]

<h2>Explanation:</h2><h2></h2>

An irrational number is a number that can't be written as a simple fraction while a rational number is a number that can be written as the ratio of two integers, that is, as a simple fraction. So in this case we have the number 2 which is ration, and we can multiply it by an irrational number $n$ such that the product is an irrational number. So any irrational number will meet our requirement because the product of any rational number and an irrational number will lead to an irrational number. For instance:

$\bullet \ 2\sqrt{2} \\ \\ 2 \ is \ rational \\ \\ \sqrt{2} \ is \ irrational \\ \\ 2\sqrt{2} \ is \ irrational \\ \\ \\ \bullet \ 2\pi \\ \\ 2 \ is \ rational \\ \\ \pi \ is \ irrational \\ \\ 2\pi \ is \ irrational$