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3 years ago

Somebody please solve this!!!

Mathematics

1 answer:

Alex73 [517]3 years ago

8 0

Answer:

See below.

Step-by-step explanation:

We know that

tanA + tan B

tan (A + B) = ---------------------

1 - tanAtanB

Substituting for A + B

tan (A + B) = tan pi/4 = 1.

tanA + tan B

So ------------------ = 1

1 - tanAtanB

Therefore tanA + tan B = 1 - tanAtanB.

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3 years ago

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Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

£440 is divided between David, Mark & Henry so that David gets twice as much as Mark, and Mark gets three times as much as H

Lesechka [4]

Mark received £ 132

Solution:

Given that £440 is divided between David, Mark & Henry

Let "d" be the share of david

Let "m" be the share of mark

Let "h" be the share of henry

Total amount is 440

Therefore,

share of david + share of mark + share of henry = 440

d + m + h = 440 ------- eqn 1

David gets twice as much as Mark

d = 2m ----- eqn 2

Mark gets three times as much as Henry

m = 3h

$h = \frac{m}{3}$ ------ eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

$2m + m + \frac{m}{3} = 440\\\\\frac{6m + 3m + m}{3} = 440\\\\10m = 1320\\\\m = 132$

Thus Mark received £ 132

8 0

4 years ago

I need help on this it’s about trig identities

Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

$\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha$

$\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha }{cos\alpha (1 + sin\alpha) }$

$\frac{1 + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha }{cos\alpha + sin\alphacos\alpha }$

$\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha }$

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2.-

sec²x - tanxsecx

$\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}$

$\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}$

$\frac{1 - sinx}{cos^{2}x }$

$\frac{1 - sinx}{1 - sin^{2}x }$

$\frac{1 - sinx}{(1 - sinx)(1 + sinx)}$

$\frac{1}{1 + sinx}$

3 0

3 years ago

When taking skinfold measurement readings only one attempt per site is necessary for an accurate reading.a. Trueb. False

Eva8 [605]

Answer: False

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3 years ago

Somebody please solve this!!!​

Somebody please solve this!!!