The quadratic equation is given by:
y = 3x² + 10x - 8
The standard equation of a parabola is given by:
y = ax² + bx + c
Where a, b, c are constants
At point (4, 80):
80 = a(4)² + b(4) + c
16a + 4b + c = 80 (1)
At point (-3, -11):
-11 = a(-3)² + b(-3) + c
9a - 3b + c = -11 (2)
At point (-1, -15):
-15 = a(-1)² + b(-1) + c
a - b + c = -15 (3)
Solving equations 1, 2 and 3 simultaneously gives:
a = 3, b = 10, c = -8
Therefore the quadratic equation becomes:
y = 3x² + 10x - 8
Find out more on quadratic equation at: brainly.com/question/1214333
Found a great explanation + 1105p = £11.05
Answer:
Step-by-step explanation:
The period of the functions 
, 
, 
or 
can be calculated as
The period of the functions 
or 
can be calculated as
A. The period of the function 
is
B. The period of the function 
is
C. The period of the function 
is
D. The period of the function 
is
E. The period of the function 
is
Percent = part/whole
It wants you to find the % of change so it's 3.25 / 3.75
And that comes out to be 0.86 (with the 6 repeating)
So you move the decimal over 2 places to find the percent.
And then it's 1 - Ans
The answer is 13.33%
<h2>T
he car is about 6.6 years old.</h2>
Step-by-step explanation:
Given : An equation for the depreciation of a car is given by 
, where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years. The value of a car is half what it originally cost. The rate of depreciation is 10%.
To find : Approximately how old is the car?
Solution :
The value of a car is half what it originally cost i.e. 
The rate of depreciation is 10% i.e. r=10%=0.1
Substitute in the equation,
Taking log both side,
Therefore, the car is about 6.6 years old.
