Answer:
Step-by-step explanation:
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<em>PQR with vertices P(–2, 9), Q(7, –3), and R(–2, –3)</em>
<em>first distance P(–2, 9), Q(7, –3) </em>
<em>The distance (d) between two points is given by the following formula: </em>
<em>Answer= 15</em>
Answer:
50
Step-by-step explanation:
im smart
Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet
Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat
By Pythagoras theorem
AC^2 = AB^2 + BC^2
(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)
AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)
Therefore they have cover a distance of 25 * (under root 11)