Ask question

Ask question

All categories

2 years ago

8

The sections of a spinner are labeled with different numbers. The probability of spinning a number greater than 20 is 0.4. The o

dds of spinning a number less than 10 are 3:5. Are you more likely to spin a number greater than 20 or to spin a number less than 10?

1 answer:

dexar [7]2 years ago

3 0

Answer:

5/6

Step-by-step explanation: probability of that is 0.83

You might be interested in

Find the missing sides.<br> (Help me)

slavikrds [6]

Answer:

2nd one

Step-by-step explanation:

when it's a 45 45 and 90 triangle, it's 1, 1, sqrt 2, but now since the 1 is sqrt 2, v is sqrt 2, and u and sqrt 2 times sqrt 2, which is 2

3 0

3 years ago

What is the value of x?

loris [4]

Answer: x = 9, y = 5

Step-by-step explanation:

If all of the sides are equal, it is an equilateral triangle. Equilateral triangles are also equiangular. The angles of a triangle add up to 180 degrees, so each angle must equal 60 degrees.

set the equation equal to 60 to solve for x

7x - 3 = 60

add three to both sides

7x = 63

divide both sides by 7

x = 9

find y by setting the equation equal to 60

11y + 5 = 60

subtract 5 from each side

11y = 55

divide both sides by 11

y = 5

6 0

2 years ago

Find the range of the function f(x)=<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7Bx%7D%5E%7B2%7D%20%2B%203x%20%2B%205

Oxana [17]

Photo math is very helpful with those type of problems

5 0

2 years ago

Read 2 more answers

7<br> Find the product of _m²n,<br> 32<br> gm²n, -m<br> -mn³, 14mn².<br> 49

DedPeter [7]

Answer: A

Step-by-step explanation:

$\left(\frac{7}{8} \right)\left(-\frac{32}{49} \right)(14)(m^{2}n)(mn^{3})(mn^{2})=\boxed{8m^{4}n^{6}}$

4 0

1 year ago

Helpppppppppp meeeeeeeeee pllzzzzzzzzz

Fantom [35]

Using the binomial distribution, it is found that there is a 0.7447 = 74.47% probability that fewer than 7 of them show up.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem, the values of the parameters are given as follows:

p = 0.7, n = 8.

The probability that fewer than 7 of them show up is given by:

[tec]P(X < 7) = 1 - P(X \geq 7)[/tex]

In which:

$P(X \geq 7) = P(X = 7) + P(X = 8)$

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{8,7}.(0.7)^{7}.(0.3)^{1} = 0.1977$

$P(X = 8) = C_{8,8}.(0.7)^{8}.(0.3)^{0} = 0.0576$

Then:

$P(X \geq 7) = P(X = 7) + P(X = 8) = 0.1977 + 0.0576 = 0.2553$

[tec]P(X < 7) = 1 - P(X \geq 7) = 1 - 0.2553 = 0.7447[/tex]

0.7447 = 74.47% probability that fewer than 7 of them show up.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

8 0

1 year ago