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Juli2301 [7.4K]

2 years ago

9

What is the image of (-7,-8) after a dilation by a scale factor of 4 centered at the origin

1 answer:

padilas [110]2 years ago

5 0

Have you ever heard the tragedy of darth plagues the wise

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Passing through (-2,-6) and parallel to the line whose equation is y=-3x+4

Licemer1 [7]

Answer:

y = -3x - 12

Step-by-step explanation:

Lines that are parallel have the same gradient.

Therefore using the point (-2,-6) you can make your own equation.

-6 will be y, -2 will be x

All you have to do is find the y-intercept which is C in <em>y</em><em>=</em><em>mx</em><em>+</em><em>c</em>

-6 = -3(-2) + c

-6 = 6 + c

-12 = c

Therefore;

<u>y = -3x - 12</u>

6 0

2 years ago

In parallelogram KLMN, NL=15. Identify NP. HELP PLEASE!!

adelina 88 [10]

Answer:

B

Step-by-step explanation:

Fact: The diagonals of a parallelogram bisect each other. If NL= 15 the NP = 1/2 NL

1/2 NL = 15/2 = 7.5.

NP = 7.5

Answer: NP = 7.5 B

7 0

3 years ago

B) The price of an electric fan is fixed 20% above its cost price. When it is sold allowing

kenny6666 [7]

Answer:

$\boxed{ \boxed{ \sf {Marked \: price \: = Rs \: 1500}}}$

$\boxed{ \bold{ \boxed{ \sf{Selling \: price = \: Rs \: 1230}}}}$

Step-by-step explanation:

Let Cost price ( C.P ) be x

<u>Finding </u><u>the </u><u>Marked </u><u>price </u><u>and </u><u>selling </u><u>price </u>

Marked price = $\sf{x + 20\% \: of \: x}$

⇒ $\sf{x + \frac{20}{100} \times x}$

⇒ $\sf{ \frac{x \times 100 + 20x}{100} }$

⇒ $\sf{ \frac{120x}{100} }$ ⇒ ( i )

Selling price = $\sf{marked \: price \: - 18\% \: of \: marked \: price}$

⇒ $\sf{ \frac{120x}{100} - \frac{18}{100} \times \frac{120x}{100} }$

⇒ $\sf{ \frac{120x}{100} - \frac{54x}{250} }$

⇒ $\sf{ \frac{120x \times 5 - 54x \times 2}{500} }$

⇒ $\sf{ \frac{600x - 108x}{500} }$

⇒ $\sf{ \frac{492x}{500} }$ ⇒ ( ii )

<u>Finding </u><u>the </u><u>value </u><u>of </u><u>x </u><u>(</u><u> </u><u>Cost </u><u>price </u><u>)</u>

$\sf{loss = cost \: price - selling \: price}$

⇒ $\sf{20 = x - \frac{492x}{500} }$

⇒ $\sf{20 = \frac{x \times 500 - 492x}{500} }$

⇒ $\sf{20 = \frac{8x}{500} }$

⇒ $\sf{8x = 10000}$

⇒ $\sf{x = \frac{10000}{8} }$

⇒ $\sf{x = \: Rs \: 1250}$

Value of x ( cost price ) = Rs 1250

<u>Now</u><u>,</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>i </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>marked </u><u>price</u>

$\sf{marked \: price = \frac{120x}{100} }$

⇒ $\sf{ \frac{120 \times 1250}{100} }$

⇒ $\sf{ \: Rs \: 1500}$

<u>Replacing </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>ii </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>selling </u><u>price</u>

$\sf{selling \: price = \frac{492 \: x}{500} }$

⇒ $\sf{ \frac{615000}{500} }$

⇒ $\sf{ \: Rs \: 1230}$

Thus , Marked price of the fan = Rs 1500

Selling price of the fan = Rs 1230

Hope I helped!

Best regards!!

6 0

3 years ago

Hi there I need help on this Monica wants to spend no more than $35

nikitadnepr [17]

Need to see more instructions.

6 0

2 years ago

HELP ME OUT PLEASE I AHVE 5 MORE QUESTIONS

ziro4ka [17]

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4 0

2 years ago