Why is math important in our everyday lives?

It is valentines day if and only if it is Feb 14th

Bond [772]

It’s the 4th option
<—> this sign thingie represents the interchanging sign like x=y y=x

7 0

3 years ago

What is the sum of the lengths, in centimeters, of the two legs of a 30-60-90 right triangle, if the length of the hypotenuse is

Nesterboy [21]

The sum of the lengths of two legs of the 30°-60°-90° right triangle is 6.69 centimeters. Using the ratio of sides for the 30°-60°-90° triangle, the sum is calculated.

<h3>What is the ratio of sides for the 30°-60°-90° triangle?</h3>

The ratio for the 30°-60°-90° triangle is 1:√3:2 or x:x√3:2x

where x corresponds to the length opposite the 30° angle and x√3 is opposite of the 60° angle and 2x is opposite to the 90° angle.

<h3 /><h3>Calculation:</h3>

It is given that the triangle is a right triangle with angles 30°-60°-90°

For such a triangle, the ratio of side lengths is x: x $\sqrt{3}$ :2x

we have the length of the hypotenuse is $2\sqrt{6}$

So, 2x = $2\sqrt{6}$

⇒ x = $\sqrt{6}$

So,

the other length of the other leg is x√3 = √6 × √3 = 3 √2

Then, the sum of these two legs = √6 + 3√2 = 6.69 centimeters.

Learn more about the ratio of sides of a 30°-60°-90° triangle here:

brainly.com/question/6695000

#SPJ4

6 0

2 years ago

A baker has 2 1/4 cups of blueberries to make three batches of muffins. How many cups of blueberries should the baker put into e

Marat540 [252]

Answer:

0.75

Step-by-step explanation:

To answer this question you need to divide 2 1/4 by 3. To make it easier turn 2 1/4 to 2.25 because .25 = 1/4.

4 0

3 years ago

In a right triangle, the hypotenuse has endpoints P(–3, 2) and Q(1, –3). On a coordinate plane, line P Q has points (negative 3,

mrs_skeptik [129]

Answer:

The length of PR is 5 units

Step-by-step explanation:

Here, we want to calculate the length of PR

Since PQ is the hypotenuse, it means that the right-angle would be between lines PR and RQ

Also, since R is on the third quadrant, then its coordinates are (-x,-y)

To get the coordinates of R since we know that we need a right angle, we drop a straight vertical line through P and a straight horizontal line through Q

What this mean is that the coordinates of R will take the x-coordinate of the point P and the y-coordinate of the point Q

Hence, we have that the coordinates of the point R is (-3,-3)

Now, we want to calculate the length of PR

PR will be the distance between the points P and R

Mathematically, to get this, we use the distance formula

That will be;

√(y2-y1)^2 + (x2-x1)^2

Thus, we have

√(2-(-3)^2 + (-3-(-3))^2

= √5^2 + 0^2

= √25 = 5 units

4 0

3 years ago

Read 2 more answers

The height, h, of a ball that is tossed into the air is a function of the time, t, it is in the air. The height in feet for t se

Ivenika [448]

Answer:

e) none

Step-by-step explanation:

The first thing that we need to realise is that this question is set to a practical example of a ball being tossed into the air for a period of time. Thus, we know that:

a) time cannot be negative

b) a ball cannot travel a negative distance in height from where it was tossed it into the air (given that this starting position is also the ground)

In the context of what the problem asks us to achieve, which is to find the domain, we now know that:

a) t ≥ 0

b) the function h(t) is only practical when h(t) ≥ 0

In other words, we know that the domain starts at t = 0, however we need to find when the ball drops back onto the ground. We can do this by solving h(t) = 0:

h(t) = -16t^(2) + 96t

0 = -16t^(2) + 96t

0 = -16t(t - 6) (Factorise -16t^(2) + 96t)

So, now we get:

-16t = 0, therefor t = 0

or

t - 6 = 0, therefor t = 6

Thus, the ball is on the ground at t = 0 seconds and t = 6 seconds; it is between these two values of t that the domain exists and that the problem is practical.

Now, looking at the multiple choice options, it seems as though none of them are correct, therefor the answer would be e) none.

The other way to work through this question (particularly if it is just multiple choice) is that, after realising that the ball is tossed into the air at t = 0 seconds and then drops at some point later, we could already discount a), b) and c) as answers since they include infinity in the domain, which is not practical for this problem.

Then, we could substitute t = 5 into the equation to get:

h(t) = -16(5)^2 + 96*5

h(t) = -16*5*5 + 96*5

h(t) = -80*5 + 96*5

Since we need h(t) to be 0 at the end value of the domain, this is not the correct answer. Thus, the answer is e) none.

6 0

3 years ago