<h3>Given</h3>
Two positive numbers x and y such that xy = 192
<h3>Find</h3>
The values that minimize x + 3y
<h3>Solution</h3>
y = 192/x . . . . . solve for y
f(x) = x + 3y
f(x) = x + 3(192/x) . . . . . the function we want to minimize
We can find the x that minimizes of f(x) by setting the derivative of f(x) to zero.
... f'(x) = 1 - 576/x² = 0
... 576 = x² . . . . . . . . . . . . multiply by x², add 576
... √576 = x = 24 . . . . . . . take the square root
... y = 192/24 = 8 . . . . . . . find the value of y using the above equation for y
The first number is 24.
The second number is 8.
Answer: 145.8
Step-by-step explanation: you have to divide 45 and 25 to get 1.8, then you get 81 and you multiply 81 x 1.8 to get your answer.
The mode is the number repeated most often, so if we arrange these numbers in order, we can see what numbers repeat the most-
1 1 1 2 3 3 5 7 8 8 9
The number that repeats the most is 1
(1 counted 3 times)
(3 counted twice)
(8 counted twice)
Answer:
$126
Step-by-step explanation:
$252/$18=$14 dollars per hour.
now take 14*9 and you get $126.
