The sum of the 8 terms of the series 1-1-3-5- ... -13 is -48
The given sequence is:
1,-1,-3, . . -13
and there are 8 terms.
The related series of this sequence is:
1-1-3-5- ... -13
Notice that the series is an arithmetic series with:
first term, a(1) = 1
common difference, d = -1 - (1) = -2
last term, a(8) = -13
To find the sum of the series, use the sum formula:
S(n) = n/2 [(a(1) + a(n)]
Substitute n = 8, a(1) = 1, a(n) = a(8) = -13 into the formula:
S(8) = 8/2 [1 + (-13)]
S(9) = 4 . (-12) = -48
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Its the identity property
Answer:
Step-by-step explanation:
The point-slope form of an equation of a line:
<em>(x₁, y₁)</em><em> - point on a line</em>
<em>m</em><em> - slope</em>
<em />
We have
Substitute:
Convert to the standard form
<em> use the distributive property</em>
<em>add 5 to both sides</em>
<em>add 4x to both sides</em>
For one 5000 can be multiplied by a number to get 500,000. 500,000 is also divisible by 5,000
10.7583 is the area of the garden
