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Nadusha1986 [10]
3 years ago
9

A pencil cost N5.50 while a pen costs N15.00. How much will 10 pencils and 6 pens cost?

Mathematics
1 answer:
Jet001 [13]3 years ago
4 0

Answer:

10 pencils cost N55

6 pens cost N90

Step-by-step explanation:

1 \: pencil \:  = 5.50 \\ 10pencils \:   = x \\ cross \: multiply \:  \\ x = 55.0\\

1 \: pen = 15.00 \\ 6 \: pens \:  = x \\ cross \: multiply \:  \\  \: x = 90

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Answer:

4.79

Step-by-step explanation:

all together the total is 38.32

you want to find one so you do

38.32 ÷ 8 = $4.79

hope it helps!

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What is the differentiation of f(x) =2x^4/5?
motikmotik
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AA3 +2=AAA CC6+6=CBB ABC=?
Ahat [919]
AA3 + 2 = AAA; 

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CC6 + 6 = CBB; </span>
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3 years ago
Solve -9.4 ≥ 1.7x + 4.2
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In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

3 0
2 years ago
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