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ExtremeBDS [4]
3 years ago
6

In three math tests, you score 91,95, and 88 points. How many points must you score on the fourth test to have an A average, or

at least 90 points?
Mathematics
1 answer:
gulaghasi [49]3 years ago
5 0
That already is a 91.1 grade average. If you want to keep that, get a 90 and above. To find your average, add all your test scores up and divide them by how many scores there are. For instance if you add all those scores up you get 274. Divide it by 3 because there are three scores and there is your average!
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lord [1]

A could be 2 while B could be 3, so -2a+3b turns into -4+9, which equals 5.

From what I know you can't really solve a a single equation with two-variables so it's just a matter of trial and error.

Just try plugging in a small number like 2 for a just to try it and you get 8b^2=72.

Divide everything by 8 to isolate b and you get that b^2=9.

Square root everything and you'll find that b=3. This is just one possible combination, I'm sure there are many more but this is obviously the one that was intended to be found.

Now that we know that a=2 and b=3 just plug them into the equation.

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7 0
3 years ago
Round to the nearest thousand and then add the rounded numbers. <br><br> 8794<br> +312
lyudmila [28]

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Step-by-step explanation:

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And so by evaluating those values we obtain:

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Now we have two answers which are our factors one where we add another where we subtract and so:

First factor:

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Second Factor:

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And so your factors are

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meaning that those are your roots/x-intercepts.


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