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Gwar [14]
3 years ago
15

Which expression is equivalent to ^4 square root

Mathematics
1 answer:
Nesterboy [21]3 years ago
7 0
\bf \sqrt[4]{\cfrac{24x^6y}{128x^4y^5}}\implies \cfrac{\sqrt[4]{4x^6y}}{\sqrt[4]{128x^4y^5}}\quad 
\begin{cases}
24=2\cdot 2\cdot 2\cdot 3\\
128=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\\
x^6=x^{4+2}\\
\qquad x^4x^2\\
y^5=y^{4+1}\\
\qquad y^4y^1
\end{cases}

\bf \cfrac{\sqrt[4]{\underline{2\cdot 2\cdot 2}\cdot 3\cdot \underline{x^4} x^2\underline{y}}}{\sqrt[4]{\underline{2\cdot 2\cdot 2}\cdot 2\cdot 2\cdot 2\cdot 2\cdot \underline{x^4} y^4\underline{y^1}}}
\implies
\cfrac{\sqrt[4]{3x^2}}{\sqrt[4]{2^4y^4}}\implies \cfrac{\sqrt[4]{3x^2}}{2y}
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lbvjy [14]

Answer:

a) 504

b) 56

c) 0.111

Step-by-step explanation:

Data provided in the question:

There are nine golf balls numbered from 1 to 9 in a bag

Three balls are randomly selected without replacement

a) 3-digit numbers that can be formed

= ^nP_r

n = 9

r = 3

= ⁹P₃

= \frac{9!}{9!-3!}

= 9 × 8 × 7

= 504

b)  3-digit numbers start with the digit 1

=  _ _ _

in the above 3 blanks first digit is fixed i.e 1

we and we have 8 choices left for the last 2 digits

Thus,

n = 8

r = 2

Therefore,

= 1 × ⁸P₂

= 1 × \frac{8!}{8!-2!}

= 1 × 8 × 7

= 56

c) Probability that the 3-digit number formed is less than 200

Now,

The number of 3-digit number formed is less than 200 will be the 3-digit numbers start with the digit 1 i.e part b)

and total 3-digit numbers that can be formed is part a)

therefore,

Probability that the 3-digit number formed is less than 200

= 56 ÷ 504

= 0.111

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3 years ago
Explain steps ASAP please and thank you
iren [92.7K]

Answer:

5\sqrt{8}

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Step-by-step explanation:

To simplify the square roots, break the number under the square root into factors. Any factors which are perfect squares may be simplified to outside the square root.

\sqrt{200}=\sqrt{25*8}  =\sqrt{25}*\sqrt{8}= 5*\sqrt{8}   =5\sqrt{8}

and

4\sqrt{108}=4\sqrt{27*4}  =4*\sqrt{27}*\sqrt{4}=4* \sqrt{9} *\sqrt{4}*\sqrt{3}    =4*3*2*\sqrt{3}=24\sqrt{3}

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Step-by-step explanation:

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