Help plz! I will give your answer a like and help too!

A border of uniform width is placed around a rectangular photograph that measures 8 inches by 10 inches. If the area of the bord

amid [387]

Answer:

width of the border is 3 inches

Step-by-step explanation:

Given data

size = 8 inches by 10 inches

area = 144 square inches

to find out

width of the border

solution

first we consider width of border is x

area of new full rectangle = (8 + 2x ) × ( 10 + 2x )

so we know area of photo = 8 × 10 = 80 square inches

and area of border = 144 square inches that is given

so new area of photo with the border is 80 + 144 = 224 square inches

and we can say that

area of full rectangle - area of the photograph = Area of Border

(8 + 2x) × (10 + 2x) – (80) = 144 square inches

80 + 16x + 20x + $4x^{2}$ – 80 = 144

$4x^{2}$ + 36x – 144 = 0

solve thios equation we get

$2x^{2}$ + 9x – 36 = 0

solve thios equation we get

(x + 12) (x – 3) = 0

so here x have two value one is negative and other is positive

so we consider only positive value

x = -12 or x = 3

width of the border is 3 inches

7 0

3 years ago

When x = -3, then y = ___

Finger [1]

Answer

answer is y=3

y=3

6 0

3 years ago

Read 2 more answers

Solve for v in the formula v = u + 10t when u = 16 and t = 4. a. v = -22 c. v = 56 b. v = 3 d. v = 40

Katen [24]

Hello!

You put 16 in for u and 4 in for t

v = (16) + 10(4)

Multiply

v = 16 + 40

Add

v = 56

The answer is v = 56

Hope this helps!

7 0

3 years ago

Find the perimeter of the figure:

Oksi-84 [34.3K]

Answer: idk but i could be

29 units

3 0

4 years ago

Read 2 more answers

The mass of the eggs laid by a certain breed of hen is a normally distributed random variable with mean 0.06kg and standard devi

Olin [163]

a (i) The number of standard size is 288 eggs

a (ii) The number of medium size is 1,476 eggs

a (iii) The number of large size is 36 eggs

b (i) The expected profit made from selling the standard size is Gh¢43.2

b (ii) The expected profit made from selling the medium size is Gh¢516.6

b (iii) The expected profit made from selling the large size is Gh¢16.2

The given parameters:

the mean of the distribution, m = 0.06 kg

standard deviation (std) of the distribution, d = 0.009 kg

number of the samples, n = 1800 eggs

(i) Find the position of "less than 0.052 kg (standard size)":

1 standard deviation below the mean = m - d

m - d = 0.06 kg - 0.009 kg = 0.051 kg

(the standard size is 1 standard deviation below the mean)

less than 1 standard deviation below the mean in a normal distribution is equal to 16% of the data samples

Number of standard size = 0.16 x 1800 = 288 eggs

(ii) Find the position of "Between 0.052 kg and 0.075kg (medium size)":

0.052 kg is 1 standard deviation below the mean

2 standard deviation above the mean = m + 2d
m + 2d = 0.06 + 2(0.009) = 0.078 kg

(the medium size is between 1 std below the mean and 2 std above the mean)

Between 1 std below the mean and 2 std above the mean in a normal distribution = (68 + 14)% = 82%

Number of medium size = 0.82 x 1800 = 1,476 eggs

(iii) Find the position of "Greater than 0.075 kg (large size)":

0.078 kg is 2 standard deviation below the mean
greater than 2 std above the mean in a normal distribution = 2 % of the data samples
Number of large size = 0.02 x 1800 = 36 eggs

Check: 288 eggs + 1476 eggs + 36 eggs = 1,800 eggs

(b) the cost of production of an egg = Gh¢0.45

the selling price of the standard size = Gh¢0.60

the selling price of the medium size = Gh¢0.80

the selling price of the large size = Gh¢0.95

(i) The expected profit made from selling the standard size:

Profit = total revenue - cost of production

Profit = 288(0.6) - 288(0.45) = Gh¢43.2

(ii) The expected profit made from selling the medium size:

Profit = total revenue - cost of production

Profit = 1476(0.8) - 1476(0.45) = Gh¢516.6

(iii) The expected profit made from selling the large size:

Profit = total revenue - cost of production

Profit = 36(0.9) - 36(0.45) = Gh¢16.2

Learn more here: brainly.com/question/22520030

3 0

3 years ago