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Lynna [10]
3 years ago
11

A bottle of medicine contains 40 doses. How many doses are in 3 1/3 bottles?

Mathematics
1 answer:
sdas [7]3 years ago
7 0
Hi there! So, there are 40 doses in 1 bottle. To find out the number of doses in 3 1/3 bottles, we have to multiply both numbers together. 3 1/3 as an improper faction is 10/3. 40/1 * 10/3 is 400/3 or 133 1/3 in simplest form. There are 133 1/3 doses of medicine in 3 1/3 bottles.
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PLEASE HELP!!!!!! 100 POINTS!!!!!!!!
FrozenT [24]

Answer:

Answers are below

Step-by-step explanation:

Hour 0                 1 bacterium

Hour 1                  3 bacterium

Hour 2                 9 bacterium

Hour 3               27 bacterium

Hour 4                81 bacterium

Hour 5            243 bacterium

Hour 6            729 bacterium

After 24 hours, the number of the bacterium will reach 282,429,536,481.

B)  This table represents exponential growth because of the number of bacterium always being multiplied by 3.

C)  The reason that any number to the zero power is one is that any number to the zero power is just the product of no numbers at all, which is the multiplicative identity, 1.

D)  Y = 1 + 3 to the power of x

E)  The rule would change by having all of the numbers multiplied by 100 since there is 100 bacterium at Hour 0.

3 0
3 years ago
How many different ways can you make 82 cents using current u.s. currency
andrew11 [14]
 <span>You can probably just work it out. 

You need non-negative integer solutions to p+5n+10d+25q = 82. 

If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80. 


So this is the same as n + 2d + 5q ≤ 16 

So now you simply have to "crank out" the cases. 

Case q=0 [ n + 2d ≤ 16 ] 

Case (q=0,d=0) → n = 0 through 16 [17 possibilities] 
Case (q=0,d=1) → n = 0 through 14 [15 possibilities] 
... 
Case (q=0,d=7) → n = 0 through 2 [3 possibilities] 
Case (q=0,d=8) → n = 0 [1 possibility] 

Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81 

Case q=1 [ n + 2d ≤ 11 ] 
Case (q=1,d=0) → n = 0 through 11 [12] 
Case (q=1,d=1) → n = 0 through 9 [10] 
... 
Case (q=1,d=5) → n = 0 through 1 [2] 

Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42 

Case q=2 [ n + 2 ≤ 6 ] 
Case (q=2,d=0) → n = 0 through 6 [7] 
Case (q=2,d=1) → n = 0 through 4 [5] 
Case (q=2,d=2) → n = 0 through 2 [3] 
Case (q=2,d=3) → n = 0 [1] 

Total from case q=2: 1 + 3 + 5 + 7 = 16 

Case q=3 [ n + 2d ≤ 1 ] 
Here d must be 0, so there is only the case: 
Case (q=3,d=0) → n = 0 through 1 [2] 

So the case q=3 only has 2. 

Grand total: 2 + 16 + 42 + 81 = 141 </span>
3 0
3 years ago
PLEASE ANSWER QUICKLY
Travka [436]

Answer:

63 :)

Step-by-step explanation:

3 0
3 years ago
(6x + 1/2) + (5x - 4 1/2)
slava [35]

Answer:

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Hope this helps :)

7 0
2 years ago
Read 2 more answers
When 59,527 is divided by 23, the quotient is 2,588 R ____
Katyanochek1 [597]

Answer: the answer is 59,527 is divided by 23, the quotient is 2,588 R 3

the answer is 3 or remainder 3

Step-by-step explanation: brainlest please

3 0
3 years ago
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