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2 years ago

A bottle of medicine contains 40 doses. How many doses are in 3 1/3 bottles?

1 answer:

7 0

Hi there! So, there are 40 doses in 1 bottle. To find out the number of doses in 3 1/3 bottles, we have to multiply both numbers together. 3 1/3 as an improper faction is 10/3. 40/1 * 10/3 is 400/3 or 133 1/3 in simplest form. There are 133 1/3 doses of medicine in 3 1/3 bottles.

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Kora has 2 graham crackers and its enough for 1 s'mores. How many s'mores would Kora make if she had 20 graham crackers?

snow_tiger [21]

Answer: 10 Smores

Step-by-step explanation:

All I did was multiply by 10

2×10=20

So...

1×10=10

3 0

3 years ago

Read 2 more answers

At the farm, Justin picks 3 bushels of fruits. The bushels weigh 8 1/4 pounds, 6 1/2 pounds, and 6 5/8 pounds. What is the avera

blondinia [14]

ANSWER

$Average \: Weight = 7 \frac{1}{8} \: bushels$

EXPLANATION

To find the average weight per bushel, we add all the three weight and divide by 3.

$Average \: Weight = \frac{8 \frac{1}{4} + 6 \frac{1}{2} + 6 \frac{5}{8} }{3}$

We convert all the mixed numbers to improper fraction to obtain,

$Average \: Weight = \frac{ \frac{33}{4} + \frac{13}{2} + \frac{53}{8} }{3}$

The least common denominator for the fractions in the numerator is 8.

This implies that,

$Average \: Weight = \frac{ \frac{66 + 52 + 53}{8} }{3}$

This simplifies to

$Average \: Weight = \frac{ \frac{171}{8} }{3}$

This gives us,

$Average \: Weight = \frac{171}{24}$

$Average \: Weight = \frac{57}{8}$

$Average \: Weight = 7 \frac{1}{8}$

7 0

3 years ago

evaluate the line integral ∫cf⋅dr, where f(x,y,z)=5xi−yj+zk and c is given by the vector function r(t)=⟨sint,cost,t⟩, 0≤t≤3π/2.

meriva

We have

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} \vec f(\vec r(t)) \cdot \dfrac{d\vec r}{dt} \, dt$

and

$\vec f(\vec r(t)) = 5\sin(t) \, \vec\imath - \cos(t) \, \vec\jmath + t \, \vec k$

$\vec r(t) = \sin(t)\,\vec\imath + \cos(t)\,\vec\jmath + t\,\vec k \implies \dfrac{d\vec r}{dt} = \cos(t) \, \vec\imath - \sin(t) \, \vec\jmath + \vec k$

so the line integral is equilvalent to

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (5\sin(t) \cos(t) + \sin(t)\cos(t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (6\sin(t) \cos(t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (3\sin(2t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \left(-\frac32 \cos(2t) + \frac12 t^2\right) \bigg_0^{\frac{3\pi}2}$

$\displaystyle \int_C \vec f \cdot d\vec r = \left(\frac32 + \frac{9\pi^2}8\right) - \left(-\frac32\right) = \boxed{3 + \frac{9\pi^2}8}$

7 0

1 year ago

Use the graph to find the slope and y-intercept to write

yaroslaw [1]

Answer:

y= -1/2x + -1

Step-by-step explanation:

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2 years ago

What is the surface area of the triangular prism? 10mm 6mm 16mm 12mm

Luda [366]

Answer:it would help of you included a photo because the base is measured differently from the triangles

Step-by-step explanation:

7 0

3 years ago