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Umnica [9.8K]
2 years ago
9

The picturre explains the question

Mathematics
2 answers:
Alina [70]2 years ago
3 0

Answer:

x = 47°

Step-by-step explanation:

Since the two angles on a line add up to 180 degrees:

x = 180-133

x = 47°

Ne4ueva [31]2 years ago
3 0

<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>U</em><em>.</em><em>.</em>

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Quick can anyone help me please, only the ones who know what they are saying lol!!!!!!!!!!!!!!!! This is attempting #7 of trying
Alecsey [184]

In a 30°-60°-90° triangle, the sides occur in a ratio of 1 to √3 to 2. In this case, <em>x</em> is half the length of the hypotenuse, so <em>x</em> = 4.

Or, using trig,

cos(30°) = <em>x</em>/8

<em>x</em> = 8 cos(30°) = 8 (1/2) = 4

3 0
3 years ago
What is the area of the parallelogram?<br> A<br> square units
irakobra [83]

Answer:

24 square units

Step-by-step explanation:

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8 0
2 years ago
Verify the pythagorean identity 1 + c o t ^2 θ = c s c ^2 θ
Grace [21]

Answer: The identity is verified. See the explanation.

Step-by-step explanation:

You must keep on mind the following identities:

csc\theta=\frac{cos\theta}{sin\theta}\\\\csc\theta=\frac{1}{sin\theta}\\\\sin^2\theta+cos^2\theta=1

Therefore, by substitution, you can rewrite the identity as shown below:

1+cot^2\theta=csc^2\theta\\\\1+\frac{cos^2\theta}{sin^2\theta}=csc^2\theta

Simpliying, you obtain:

\frac{sin^2\theta+cos^2\theta}{sin^2\theta}=csc^2\theta\\\\\frac{1}{sin^2\theta}=csc^2\theta\\\\csc^2\theta=csc^2\theta

The identity is verified.

6 0
3 years ago
A right triangle has leg measures of 8 and 15 inches. What is the area and perimeter of the triangle?
rewona [7]

Hello!

<h3><em><u>Answer</u></em></h3>

The area of the right triangle is 30 in^{2}. The perimeter is 40 in.


<h3><em><u>Explanation</u></em></h3>

First, we must find the measure of the hypotenuse of the triangle by using the Pythagorean Theorem.

a^{2} + b^{2} = c^{2}

8^{2} + 15^{2} = c^{2}

64 + 225 = c^{2}

√289 = c^{2}

17 = c

Now that we have all the side lengths, we can use the formulas to find the area and perimeter.

<h3>AREA:</h3>

A = \frac{bh}{2}

A = (15 × 8) ÷ 2

A = 30

<h3>PERIMETER:</h3>

P = a + b + c

P = 8 + 15 + 17

P = 40


8 0
3 years ago
Use the graphing calculator to graph the quadratic function y=2x^2 + 2x -40. what are the zeros of the function
ahrayia [7]

Answer:

The zeroes of this function are x=-5 and x=4

3 0
3 years ago
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