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kompoz [17]
3 years ago
15

Groundhog's Day is on February 2nd each year. On this day, in Punxsatawney, Pennsylvania, thousands of onlookers watch to see if

Phil, the groundhog, will cast a shadow. If he does, then six more weeks of winter are predicted. If he doesn't, then an early spring is predicted. Historically, Phil's prediction has only been correct about 40% of the time.
Using complete sentences, design a simulation to determine the probability that Phil's prediction will be correct at least two out of the next three years. Make sure to explain how you would use the simulation to determine the probability.
Mathematics
1 answer:
Dominik [7]3 years ago
3 0

Answer:

in the theory of chances, it states that no matter what the average, chance can change it no matter what. Like someone getting good chances in a video game 2 times in a row. its rare, but compared to how many people play the game and how often, it was bound to happen at some point. the chances could be tiny, but it could still happen. just like if 100 monkeys were on typewriters typing 60 wpm, one would eventually type Abraham Lincoln. low chance, but if all these monkeys are doing it enough, it would happen eventually. so, it is entirely possible that 2/3 of his next predictions will be correct.

Step-by-step explanation:

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F
viktelen [127]

Answer:

what is this.

Please write in a proper way.

5 0
2 years ago
Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
3 years ago
Solve the radical equation and what is the extraneous solution to the radical equation
miskamm [114]

Remove the radical by raising each side to the index of the radical.

x=-1

7 0
3 years ago
Read 2 more answers
Pls anyone I need answer of this urgent PLEASE
oksian1 [2.3K]

Answer:

Q.#1 is a

Q.#2 is d

Step-by-step explanation:

hope this helps:)

5 0
2 years ago
Please explain how you got your answer!!! The dot plots below show the ages of students belonging to two groups of salsa classes
Rudik [331]

Answer:

Group b most likely has a lower mean age of salsa students

Step-by-step explanation:

Arithmetic Mean of the data is the average of a set of numerical values, calculated by adding them together and dividing by the number of terms in the set.

Here we are given with two groups that are Group A and Group B

both having total number of students = 20

Here the mean age of the data is addition of the all ages of different students divided by total number of students.

For group a

total age of the group = 3 × 5 + 4 × 10 + 6 × 17 + 4 × 24 + 3 × 29

= 15 + 40 + 102 + 96 + 87

=340

The mean age of salsa students= 340 ÷ 20 = 17

For group b

total age of the group = 6 × 7 + 3 × 10 + 4 × 14 + 5 × 16 + 2 × 21

= 42 + 30 + 56 + 80 + 42

=250

The mean age of salsa students= 250 ÷ 20 = 12.5

So the group b most likely has a lower mean age of salsa students

Learn more about Arithmetic Mean here - brainly.com/question/24688366

#SPJ10

7 0
2 years ago
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