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Natasha2012 [34]
3 years ago
5

Deshad runs a river tubing company that serves 300 customers a day during sunny, summer days. He knows that 45% of the customers

rent life jackets. Suppose that Deshad calculates the daily proportion p ^ on top of customers who rent life jackets from his sample of 300. We can assume the customers each day represent a random sample.
Mathematics
1 answer:
Anika [276]3 years ago
8 0

Answer:

ccccccccccccccc

Step-by-step explanation:

ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

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A train traveling nonstop to its destination is able to make the trip at an average speed of 70 miles per hour. On the return tr
larisa86 [58]

Answer:

Return trip travel time: 7h

Step-by-step explanation:

Let d be the distance.

Index 1 refers to initial trip, index 2 refers to the return trip.

v1=70mi/h

v2=40mi/h

t2=t1+3h, or t1=t2-3h (travel times)

d=v1×t1=v2×t2

v1×(t2-3)=v2×t2

v1 t2 -3 v1=v2 t2

v1 t2 - v2 t2=3 v1

t2(v1-v2)=3v1

t2=3v1/(v1-v2)

Or

t2=3×70/(70-40)=3×70/30=7h

3 0
3 years ago
Evaluate the following integral over the specified region. Assume (r comma theta )(r,θ) are polar coordinates. ModifyingBelow In
topjm [15]

Answer:

Step-by-step explanation:

We have to integrate the function

16+x^2+y^2 over the region

1\leq r\leq 3\\0\leq \theta \leq \pi

Let us convert into polar coordinates

x=cost : y = sint

Then we get dxdy = rdr dt

So we get the integral as

\int \int _R (16+x^2+y^2)^2 dxdy\\= \int\limits^3_0 \int\limits^\pi_0( {16+r^2}^2) (r)drdt\\ =(t) (\frac{(16+r^2)^3}{6}

Substitute the limits to get

Answer

=(\pi-0) [\frac{1}{6} (25-16)\\=1.5 \pi

4 0
3 years ago
How many cups are there in 697 pints?
Rudiy27

Answer:

1674.12

Step-by-step explanation:

I hope it helps.

4 0
3 years ago
For 300 trading​ days, the daily closing price of a stock​ (in $) is well modeled by a Normal model with mean ​$196.99 and stand
KATRIN_1 [288]

Answer:

a) 2.5% b) 84% c) 95% d) D. The more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

Step-by-step explanation:

For a) b) and c) we will use the empirical rule, so, we can observe the image shown below

a) 211.23 is exactly two standard deviation above the mean, so, the probability that on a randomly selected day in this period the stock price closed above 211.23 is 2.35% + 0.15% = 2.5%  

b) 204.11 represents exactly one standard deviation above the mean, so, the probability of being below 204.11 is 50% + 34% = 84%

c) The probability of getting a value between 182.75 and 211.23 is 95%, this because 182.75 is exactly two standard deviations below the mean and 211.23 is exactly two standard deviations above the mean.

d) The z-score related to 208 is z_{1} = (208-196.99)/7.12 = 1.5 and the z-score related to 185 is  z_{2} = (185-196.99)/7.12 = -1.7, therefore, the more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

5 0
3 years ago
Plz help will mark brainliest
Snowcat [4.5K]

Answer:

20

Step-by-step explanation:

First step is finding an angle in the rightmost triangle (angle K)

Using TOA we have

Tan(x)=4/8

x=26.565

which means that 90-26.565= 63.4349 will give us angle K in regards to the left triangle

Using this we can solve for JM

Tan(63.4349)=x/8

8tan(63.4349=x

x=16

So if JM = 16

and LM=4

take their sum to find JL

16+4=20

4 0
3 years ago
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