Answer:
Return trip travel time: 7h
Step-by-step explanation:
Let d be the distance.
Index 1 refers to initial trip, index 2 refers to the return trip.
v1=70mi/h
v2=40mi/h
t2=t1+3h, or t1=t2-3h (travel times)
d=v1×t1=v2×t2
v1×(t2-3)=v2×t2
v1 t2 -3 v1=v2 t2
v1 t2 - v2 t2=3 v1
t2(v1-v2)=3v1
t2=3v1/(v1-v2)
Or
t2=3×70/(70-40)=3×70/30=7h
Answer:
Step-by-step explanation:
We have to integrate the function
over the region

Let us convert into polar coordinates
x=cost : y = sint
Then we get dxdy = rdr dt
So we get the integral as

Substitute the limits to get
Answer
=
Answer:
1674.12
Step-by-step explanation:
I hope it helps.
Answer:
a) 2.5% b) 84% c) 95% d) D. The more unusual day is if the stock closed below $185 because it has the largest absolute z-score.
Step-by-step explanation:
For a) b) and c) we will use the empirical rule, so, we can observe the image shown below
a) 211.23 is exactly two standard deviation above the mean, so, the probability that on a randomly selected day in this period the stock price closed above 211.23 is 2.35% + 0.15% = 2.5%
b) 204.11 represents exactly one standard deviation above the mean, so, the probability of being below 204.11 is 50% + 34% = 84%
c) The probability of getting a value between 182.75 and 211.23 is 95%, this because 182.75 is exactly two standard deviations below the mean and 211.23 is exactly two standard deviations above the mean.
d) The z-score related to 208 is
= (208-196.99)/7.12 = 1.5 and the z-score related to 185 is
= (185-196.99)/7.12 = -1.7, therefore, the more unusual day is if the stock closed below $185 because it has the largest absolute z-score.
Answer:
20
Step-by-step explanation:
First step is finding an angle in the rightmost triangle (angle K)
Using TOA we have
Tan(x)=4/8
x=26.565
which means that 90-26.565= 63.4349 will give us angle K in regards to the left triangle
Using this we can solve for JM
Tan(63.4349)=x/8
8tan(63.4349=x
x=16
So if JM = 16
and LM=4
take their sum to find JL
16+4=20