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Sav [38]
3 years ago
5

Help with number 12 please

Mathematics
1 answer:
Troyanec [42]3 years ago
4 0
 <span>The fifth power of ten would not be represented. 
Each individual digit would be shown as a power of ten. 
982 would be the sum of: 
9 times 100. (100 is 10 to the second power) 
plus 
8 times 10. (10 is 10 to the first power.) 
plus 
2 times 1. (I is 10 to the zero power.) 

The only significant digit represented by a zero is the "hundred thousands" 
(100,000 is 10 to the fifth power.)</span>

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First, suppose she has only quarters and nickels and no other coins.  Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this.  So she must have at least one other type of coin.

Assume she has only quarters, nickels, and dimes.  Then if D is the number of dimes, 5C +  25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32.  The smallest D can be is 2, leaving 3C = 30 and thus C = 10.  So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.

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