Answer:
10 whole boards
Step-by-step explanation:
1. 36 divided by 3.75 = 9.6
2. Round to the nearest whole number
3. 9.6 rounded = 10
I got 168 because if you multiply 8x12 then you would get 96 and on the sides u need to multiply 3x12
2 nuumbers multiply to 8 an addd to 6
factor 8 and add teh factor pairs
1,8
2,4
8+1=9
2+4=6
numbers are 2 and 4
if you were to solve it the
xy=8
x+y=6
y=6-x
x(6-x)=8
6x-x^2=0
0=x^2-6x+8
facotr
0=(x-2)(x-4)
set each to zero
x-2=0
x=2
x-4=0
x=4
x=2 or 4 and since they are interchangable, the numbes are 2 and 4
Dy/dx = y/(x^2)
dy/y = dx/(x^2)
int[dy/y] = int[dx/(x^2)] ... apply integral to both sides
ln(|y|) = (-1/x) + C
|y| = e^{(-1/x) + C}
|y| = e^C*e^(-1/x)
|y| = C*e^(-1/x)
y = C*e^(-1/x)
So you have the correct answer. Nice job.
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Check:
y = C*e^(-1/x)
dy/dx = d/dx[C*e^(-1/x)]
dy/dx = d/dx[-1/x]*C*e^(-1/x)
dy/dx = (1/(x^2))*C*e^(-1/x)
is the expression for the left hand side (LHS)
y/(x^2) = [C*e^(-1/x)]/(x^2)
y/(x^2) = (1/(x^2))*C*e^(-1/x)
is the expression for the right hand side (RHS)
Since LHS = RHS, this confirms the solution for dy/dx = y/(x^2)
Answer:
Step-by-step explanation:
hello :
5x²+8x-4 quadratic expression when : a = 5 and b=8 and c= -4
∆ = b²-4ac ∆ = 8²-4(5)(-4) = 64 +80 = 144 = 12²
X1 = ( -b -√∆)/2a X1 = (-8-12)/10 = -20/10= -2
X2 =(-b+√∆)/2a X2 = (-8+12)/10 = 4/10 = 2/5
us factorisation : a(X-X1)(X-X2)
5x²+8x-4= 5(x+2)(x-2/5) = (x+2)(5x-2)
you can verify ; (x+2)(5x-2) = 5x²-2x+10x-4 = 5x²+8x-4
