Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.
I'd say it is A but I think you have made a tpyo
It should be 2*PI*radius^2 + 2*PI*radius*height
Answer:
there you go bro. 168 degrees for each angle
Step-by-step explanation:
To calculate the central angle visualize a circle in the center of the polygon. A circle has 360 degrees. Divide 360 by the number of sides and that will tell you the central angle size. So 360 divided by 30 equals 18 degrees.
To find the base angle use this formula
180(n-2)/n where n is the number of sides of a regular polygon.
When you plug in 30 for n
Answer:
.
Step-by-step explanation:
Answer:
2/5
Step-by-step explanation:
m=change in y/change in x
m=
m = 6-(4)/3-(-2)
m=2/3-(-2)
m= 2/3+2
m=2/5
