For this case we have the following equation:
d = 0.5 + 5t
We will describe the equation step by step.
0.5: Initial distance Jillian walked
5: speed with which Jillian begins to jog
t: independent variable that indicates the number of hours
y: dependent variable that indicates the distance traveled in miles
Answer:
The variable variable is time and the dependent variable is distance.
Answer:
a, y =3/x
x = 0.5 => y = 3/0.5 = 6
x = 1 => y = 3/1 = 3
x = 2 => y = 3/2 = 1.5
x = 3 => y = 3/3 = 1
x = 4 => y = 3/4 = 0.75
b,
y = 3/x passes (0.5, 6) => A is correct
Hope this helps!
The number of permutations of the 25 letters taken 2 at a time (with repetitions) is:
The number of permutations of the 9 digits taken 4 at a time (with repetitions) is:
Each permutation of letters can be taken with each permutation of digits, therefore the total number of possible passwords is:
if you start at the point (0,1), you are going to go up and over to (-2,4), which means you will go up 3 and to the left, which means negative, 2
rise/run
3/-2
Answer:
x₂ = 7.9156
Step-by-step explanation:
Given the function ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
If f(x) = ln(x)+x-10
f'(x) = 1/x + 1
f(9) = ln9+9-10
f(9) = ln9- 1
f(9) = 2.1972 - 1
f(9) = 1.1972
f'(9) = 1/9 + 1
f'(9) = 10/9
f'(9) = 1.1111
x₁ = x₀ - f(x₀)/f'(x₀)
x₁ = 9 - 1.1972/1.1111
x₁ = 9 - 1.0775
x₁ = 7.9225
x₂ = x₁ - f(x₁)/f'(x₁)
x₂ = 7.9225 - f(7.9225)/f'(7.9225)
f(7.9225) = ln7.9225 + 7.9225 -10
f(7.9225) = 2.0697 + 7.9225 -10
f(7.9225) = 0.0078
f'(7.9225) = 1/7.9225 + 1
f'(7.9225) = 0.1262+1
f'(7.9225) = 1.1262
x₂ = 7.9225 - 0.0078/1.1262
x₂ = 7.9225 - 0.006926
x₂ = 7.9156
<em>Hence the approximate value of x₂ is 7.9156</em>
