Question

F(x)=x^2+3+6 and g(x)=x-3/2 solve for f(g(x)) when x=1

Answer 1

1). f(x) = x² + 3+ 6 
     f(x) = 1² + 3 + 6
     f(x) = 1 + 3 + 6
     f(x) = 4 + 6 
     f(x) = 10
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2). g(x) = x - 3/2 
      g(x) = 1 - 3/2
     
      g(x) = 1 - 3
               -------- = -1
                   2

g(x) = -1
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