Well there both even numbers so the gcf factor would have to be even also

60 = 1,2,3,4,5,6,10,12,15,20,30,60

72 = 1,2,3,4,6,8,9,12,18,24,36,72

The Gcf would be 12

3 0

3 years ago

(x³ + ³) / (x - y)<br> Do not include parentheses in your answer.

Lubov Fominskaja [6]

The simplified expression of $\frac{x^3 + (-y)^3}{(x - y}$ is $x^2+xy+y^2$

<h3>Complete question</h3>

Simplify the expression: (x³ + (-y)³) / (x - y)

Do not include parentheses in your answer.

<h3>How to simplify the expression?</h3>

The expression is given as:

$\frac{x^3 + (-y)^3}{(x - y}$

Open the inner bracket

$\frac{x^3 -y^3}{(x - y}$

Apply the difference of two cubes to the numerator

$\frac{(x-y)(x^2+xy+y^2)}{(x - y}$

Cancel out the common factors

$x^2+xy+y^2$

Hence, the simplified expression of $\frac{x^3 + (-y)^3}{(x - y}$ is $x^2+xy+y^2$

Read more about expressions at:

brainly.com/question/723406

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4 0

2 years ago

What is the value of tan A?

Ronch [10]

For the given triangle, the tan of angle A equals $\frac{3}{4} = 0.75.$

Step-by-step explanation:

Step 1:

In the given triangle for angle A, the opposite side has a length of 6 cm, the adjacent side has a length of 8 cm while the hypotenuse of the triangle measures 10 cm. To calculate the tan of angle A we divide the opposite side's length by the adjacent side's length.

$tan A = \frac{oppositeside}{adjacent side}.$

Step 2:

The opposite side's length = 6 cm.

The adjacent side's length = 8 cm.

$tan A = \frac{oppositeside}{adjacent side} = \frac{6}{8} = \frac{3}{4} = 0.75.$

6 0

3 years ago