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Semmy [17]
3 years ago
10

What is the value of tan A?

Mathematics
1 answer:
Ronch [10]3 years ago
6 0

For the given triangle, the tan of angle A equals \frac{3}{4} = 0.75.

Step-by-step explanation:

Step 1:

In the given triangle for angle A, the opposite side has a length of 6 cm, the adjacent side has a length of 8 cm while the hypotenuse of the triangle measures 10 cm. To calculate the tan of angle A we divide the opposite side's length by the adjacent side's length.

tan A = \frac{oppositeside}{adjacent side}.

Step 2:

The opposite side's length = 6 cm.

The adjacent side's length = 8 cm.

tan A = \frac{oppositeside}{adjacent side} = \frac{6}{8} = \frac{3}{4} = 0.75.

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Bongani and Jane are friends. Bongani takes Jane's maths test paper and will not tell her what her number of points is. He knows
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Answer:

Jane has 6 points, and B has 8 points.

Step-by-step explanation:

If both of them in total have 14 points, and B has 2 more points than Jane, this means that:

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14-2=12

Since these are being divided to two people, you have to divide 12 too

12/2 = 6

6 is Jane's number of points. And now to find B just add 2 points to it which is 8.

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4 0
3 years ago
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Step-by-step explanation:

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Write an equation in point-slope form, slope intercept form, and standard form for a line that passes through (-2,8) with slope
a_sh-v [17]

9514 1404 393

Answer:

  • y -8 = 8/5(x +2)
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Step-by-step explanation:

Since you're given a point and slope, it is convenient to start with that form.

<u>Point-slope form</u>

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

  y -8 = 8/5(x +2) . . . point-slope equation

__

<u>Slope-intercept form</u>

  y = mx + b . . . . . line with slope m and y-intercept b

The above equation can be rearranged to this form.

  y = 8/5x +16/5 +8

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<u>Standard form</u>

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6 0
3 years ago
I need help !!!!!!!!!​
german

Answer:

a. 14

b. 10

c. 11

Step-by-step explanation:

You need to use the distance formula.

\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2}}

Ex: (1,2) and (1,16)

You will need to lable each

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2nd Point: 1 will be x_{2} and 16 will be y_{2}

Then you will need to plug it in

\sqrt{(1-1)^{2} +(16-2)^{2}}

5 0
3 years ago
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