Answer:
Step-by-step explanation:
You multiply them together; to get 8.55
Answer:
∠WXY = 107°
Step-by-step explanation:
In a trapezoid, adjacent angles are supplementary, meaning they add up to 180°. ∠W and ∠WXY are adjacent, so they are supplementary. 180° - 73° = 107°.
Another way to do this is to know that there are 360° in a trapezoid. This is a right trapezoid, so two of the angles are 90°. One angle is 73°. 90° + 90° + 73° = 253°. 360° - 253° = 107°.
I hope this helps :))
Answer:
89=14-5x
Step by step
Because 14 is how many he keeps and x5 is how many he gives to his cousins in total
Answer:
One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:
Iaₙ₊₁I < IaₙI
This means that the absolute value of the terms must decrease as n increases.
Then we must have:
![\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%20-2%29%5En%7D%7Bn%2A3%5En%7D%20%3E%20%5Cfrac%7B%28x%20-2%20%29%5E%7Bn%2B1%7D%7D%7B%28n%20%2B%201%29%2A3%5E%7Bn%2B1%7D%7D)
We can write this as:
![\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%20-2%29%5En%7D%7Bn%2A3%5En%7D%20%3E%20%5Cfrac%7B%28x%20-2%20%29%5E%7Bn%2B1%7D%7D%7B%28n%20%2B%201%29%2A3%5E%7Bn%2B1%7D%7D%20%3D%20%5Cfrac%7B%28x%20-2%29%5En%7D%7B%28n%20%2B%201%29%2A3%5En%7D%20%2A%20%5Cfrac%7B%28x%20-%202%29%7D%7B3%7D)
If we assume that n is a really big number, then:
n + 1 ≈ 1
And we can write:
![\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%20-2%29%5En%7D%7Bn%2A3%5En%7D%20%3E%20%5Cfrac%7B%28x%20-2%29%5En%7D%7B%28n%29%2A3%5En%7D%20%2A%20%5Cfrac%7B%28x%20-%202%29%7D%7B3%7D)
Then we have the inequality
![1 > (x - 2)/3](https://tex.z-dn.net/?f=1%20%3E%20%28x%20-%202%29%2F3)
And remember that this must be in absolute value, then we will have that:
-1 < (x - 2)/3 < 1
-3 < x - 2 < 3
-3 + 2 < x < 3 + 2
-1 < x < 5
The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.