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3 years ago

What is the volume of a sphere with a radius of 1 foot

Mathematics

2 answers:

navik [9.2K]3 years ago

7 0

The volume is 4.19ft³ Hope it helps <3

statuscvo [17]3 years ago

7 0

4.19ft^3..... I hope this helps

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Help me to do this question plz <br>I will make you as brainlist

romanna [79]

Answer:

I don't understand the language but I can do it

6 0

3 years ago

$3000 is invested at 3% annual interest for 3 years.<br> a. Simple Interest b. Compound Interest

stich3 [128]

Answer:

a. $270

b. $3,278.18

Step-by-step explanation:

Given that

The principal amount is $3,000

Annual rate of interest is 3%

And, the time period is 3 years

We need to find out the simple interest & compound interest

The following formulas should be used

a. For simple interest

= Principal × rate of interest × time period

= $3,000 × 3% × 3 years

= $270

b. For compound interest

= Principal × (1 + rate of interest)^time period

= $3,000 × (1 + 0.03)3

= $3,000 × 1.03^3

= $3,278.18

8 0

3 years ago

A lumber company is making boards that are 2920.0 millimeters tall. If the boards are too long they must be trimmed, and if the

Effectus [21]

Answer:

The value of the test statistic is of 0.22.

Step-by-step explanation:

Our test statistic is:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the expected mean, $\sigma$ is the standard deviation(square root of the variance) and n is the size of the sample.

A lumber company is making boards that are 2920.0 millimeters tall.

This means that $\mu = 2920$ .

A sample of 12 is made, and it is found that they have a mean of 2922.7 millimeters with a variance of 121.00.

This means that $X = 2922.7, n = 12, \sigma = \sqrt{121} = 11$ . So

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$t = \frac{2922.7 - 2922}{\frac{11}{\sqrt{12}}}$

$t = 0.22$

The value of the test statistic is of 0.22.

4 0

2 years ago

Below are the range and standard deviation for a set of data. Use the range rule of thumb and compare it to the standard deviati

Liula [17]

Solution: We are given:

$Range =2.76$

$Standard-deviation=0.807$

Now let's find the estimated value of standard deviation using the range rule of thumb. According to range rule of thumb, the estimate of standard deviation is:

$S\approx \frac{2.76}{4}= 0.690$

Therefore the estimated standard deviation is 0.690

is this an acceptable approximation?

Answer: c. Yes, because the error of the range rule of thumb's approximation is less than 15%.

Explanation:

The difference between estimated standard deviation and actual standard deviation is:

0.807 - 0.690 = 0.117

Now let's find the percentage of error

$\frac{0.117}{0.807} \times 100= 14.50\%$ .

Therefore, the error of the range rule of thumb's approximation is less than 15%.

4 0

3 years ago

What are the leading coefficient and degree of the polynomial?<br> -1+23x² +8x

lyudmila [28]

It is 12 it’s is 12 it has to be 12

4 0

1 year ago