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aleksley [76]
3 years ago
11

What is the volume of a sphere with a radius of 1 foot

Mathematics
2 answers:
navik [9.2K]3 years ago
7 0
The volume is 4.19ft³ Hope it helps <3
statuscvo [17]3 years ago
7 0
4.19ft^3..... I hope this helps

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A high school drama club is selling tickets for a fundraiser event. Based on data from past events, the number of tickets sold c
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600 or 16

Step-by-step explanation:

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Arlan states, "If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a rhombus." Decide if his statem
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The answer is b. the correct thing to say is "<span>If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a Rectangle."</span>
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3 years ago
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What is -2x-18=-4x-6<br> need step by step
Kazeer [188]

Answer:

\boxed {x = 6}

Step-by-step explanation:

Solve for the value of x:

-2x - 18 = -4x - 6

-Take 4x and add it to -2x:

-2x - 18 + 4x = -4x + 4x  - 6

2x - 18 = -6

-Add both sides by 18:

2x - 18 + 18 = -6 + 18

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-Divide both sides by 2:

\frac{2x}{2} = \frac{12}{2}

\boxed {x = 6}

Thus, the value of x is 6.

6 0
3 years ago
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A rectangle in the xy-coordinate plane is formed by the points (1,−4), (1,6), (3,−4), and (3,6). What is the perimeter of this r
Airida [17]

Answer:

Perimeter of the rectangle=20+2\sqrt{104}

Step-by-step explanation:

The perimeter of the rectangle with the given coordinates is the sum of its all four sides:

Let the points be A(1,-4), B(1,6), C(3,-4) and D(3,6)

Finding the sides of the rectangle using the Distance formula:

AB=

               \sqrt{(1-1)^2+(6-(-4))^2} \\\\=\sqrt{0+10^2} \\\\=\sqrt{100}\\\\ =10

BC

            =\sqrt{(3-1)^2+(-4-6)^2} \\\\=\sqrt{2^2+(-10)^2}\\\\ =\sqrt{4+100} \\\\=\sqrt{104}

CD=

             \sqrt{(3-3)^2+(6-(-4))^2} \\\\=\sqrt{0+10^2} \\\\=\sqrt{100} \\\\=10

AD=

            \sqrt{(3-1)^2+(6-(-4))^2} \\\\=\sqrt{2^2+10^2} \\\\=\sqrt{4+100}\\\\ =\sqrt{104}

 Perimeter of the rectangle=AB+BC+CD+AD

                                    =10+\sqrt{104}+ 10+\sqrt{104}

Perimeter of the rectangle=20+2\sqrt{104}

7 0
3 years ago
Standing in your tree house, 50 feet off the ground, you look down at a 60° angle and notice a frisbee. approximately how many
andrew11 [14]
Draw a diagram
assuming you are directly over the base of the tree

we need to find the ratio between the adjacent angle and oposite angle

adjacent angle is the disatnce from frisbee to base of tree
oposite angle is 50ft

so
tan=oposite/adjacent
tan(60°)=50/?
?tan(60°)=50
?=50/tan(60°)
use your calculator
?≈28.8675
so about 29ft away from the base of the tree is the frisbee

6 0
3 years ago
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