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3 years ago

What is the volume of a sphere with a radius of 1 foot

Mathematics

2 answers:

navik [9.2K]3 years ago

7 0

The volume is 4.19ft³ Hope it helps <3

statuscvo [17]3 years ago

7 0

4.19ft^3..... I hope this helps

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Find the slope<br> (-2,2) (5,3)

aalyn [17]

Use the expression:

y₂ - y₁
--------
x₂ - x₁

choose one set to be your ₁, and the other to be your ₂. Plug them in

3 - 2 1
------- = ----------
5 - (-2) 7

your slope will be 1/7

hope this helps

6 0

4 years ago

What is 3 multiplied by 5/8 as a mixed number

kati45 [8]

3 * (5/8)=
15/8=
1 and 7/8

6 0

4 years ago

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HELPPP PLEASE!!!<br> What is the interior angle sum of a shape that has 45 sides?

ANTONII [103]

15840 degrees

Hope this helps!

7 0

3 years ago

You are buying decorations for a birthday party. Six rolls of crepe paper and 20 balloons cost $11.90. After you start decoratin

olga2289 [7]

Answer: $1.15

Step-by-step explanation:

The question is How much did each roll of crepe paper cost?

Let the cost of crepe paper be x

Let the cost of balloons be y.

Six rolls of crepe paper and 20 balloons cost $11.90. This will be:

6x + 20y = 11.90 ......... i

2 more rolls of crepe paper and 15 more balloons for $6.05. This will be:

2x + 15y = 6.05 ......... ii

6x + 20y = 11.90 ......... i

2x + 15y = 6.05 ......... ii

Multiply equation i by 15

Multiply equation ii by 20

90x + 300y = 178.50 ........ iii

40x + 300y = 121 ........ iv

Subtract iv from iii

50x = 57.50

x = 57.50/50

x = 1.15

Therefore, a crepe paper cost $1.15

6 0

3 years ago

Complete the table of values for the function f(x) = (1/3)x for a, b, and c. x : -2, -1, 0, 1, 2. f(x) : a, b, c, 1/3, 1/9

balu736 [363]

Given:

The function is

$f(x)=\left(\dfrac{1}{3}\right)^x$

To find:

The missing values for a, b, and c in the given table.

Solution:

We have,

$f(x)=\left(\dfrac{1}{3}\right)^x$

At x=-2,

$f(-2)=\left(\dfrac{1}{3}\right)^{-2}$

$a=\left(3\right)^{2}$ $\left[\because \left(\dfrac{a}{b}\right)^{-n}=\left(\dfrac{b}{a}\right)^{n}\right]$

$a=9$

At x=-1,

$f(-1)=\left(\dfrac{1}{3}\right)^{-1}$

$b=\left(3\right)^{1}$ $\left[\because \left(\dfrac{a}{b}\right)^{-n}=\left(\dfrac{b}{a}\right)^{n}\right]$

$b=3$

At x=0,

$f(0)=\left(\dfrac{1}{3}\right)^{0}$

$c=1$ $\left[\because a^0=1, a\neq 0\right]$

Therefore, the missing values of a,b and c are 9, 3, and 1 respectively.

8 0

3 years ago

Read 2 more answers