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Alexxx [7]
2 years ago
15

Urgent! Quadrilateral ABCD is inscribed in the circle. What is the measure of angle C?​

Mathematics
1 answer:
AnnyKZ [126]2 years ago
3 0

Answer: 92

Step-by-step explanation: Angles in an inscribed quad are supplementary and add to 360.

First solve for x:

2x+34=180

x = 73

Then, solve for c

3x + 49 + c = 360

3(73) + 49 + c = 360

268 + c = 360

c = 92

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What's the property of equality of r- 20 = 30
galina1969 [7]

Answer:

r= 10

Step-by-step explanation:

30 - 20 = 10

3 0
2 years ago
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Kay [80]

- (4x - 15) \geqslant  - 9(3 + x) \\  - 4x + 15 \geqslant  - 27 - 9x \\  - 4x + 9x \geqslant  - 27 - 15 \\ 5x \geqslant  - 42 \\ x \geqslant  - 8 \dfrac{2}{5}


21 + x > 2( - 2 - 5x) + 6x \\ 21 + x >  - 4 - 10x + 6x \\ x + 10x - 6x >  - 4 - 21 \\ 5x >  - 25 \\ x >  - 5

Hope this helps. - M
5 0
2 years ago
Gail Leonard�s monthly take home pay is $5,000 She has a $600 mortgage payment, $750 car payment, $120 student loan payment, and
storchak [24]
I am pretty sure your correct answer is 3380.
4 0
3 years ago
What is the answrs for number 9, with proof
Nuetrik [128]

Answer:

1. 30

2. 34

Step-by-step explanation:

2(4(3) + 3)

2(12 + 3)

2(15)

= 30

12(3) - 2

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hope this helps :)

8 0
2 years ago
Find an equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)
sattari [20]

Answer:

(x+5)^{2}=-4(y+3)

Step-by-step explanation:

Given:

Focus point = (-5, -4)

Vertex point = (-5, -3)

We need to find the equation for the parabola.

Solution:

Since the x-coordinates of the vertex and focus are the same,

so this is a regular vertical parabola, where the x part is squared. Since the vertex is above the focus, this is a right-side down parabola and p is negative.

The vertex of this parabola is at (h, k) and the focus is at (h, k + p). So, directrix is y = k - p.

Substitute y = -4 and k = -3.

-4 = -3+p

p=-4+3

p=-1

So the standard form of the parabola is written as.

(x-h)^{2}=4p(y-k)

Substitute vertex (h, k) = (-5, -3) and p = -1 in the above standard form of the parabola.

So the standard form of the parabola is written as.

(x-(-5))^{2}=4(-1)(y-(-3))

(x+5)^{2}=-4(y+3)

Therefore, equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)

(x+5)^{2}=-4(y+3)

7 0
3 years ago
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