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tamaranim1 [39]
3 years ago
7

Can someone please help me with this problem?

B15%29%7D%7B%28x%2B3%29%7D%20" id="TexFormula1" title=" \frac{( x^{2} +8x+15)}{(x+3)} " alt=" \frac{( x^{2} +8x+15)}{(x+3)} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
hodyreva [135]3 years ago
7 0
First, factor the expression on the top. What two numbers add to get 8 and multiply to 15? 5 and 3! so the top expression factors to (x+3)(x+5). You can cancel the x+3 from the denominator and end up with x+5. Make sense?
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Hello from MrBillDoesMath!

Answer:

No


Discussion:

If the functions are inverses, then f(g(x)) = x  for appropriate x. Consider x = 1.

g(1) = 1/ (5(1) + 1) = 1/6

f(g(1)) = f (1/6) =  5(1/6) + 1/ (1/6) = 5/6 + 6 = 6 5/6   <> 1

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