A school is organizing a cookout where

Write a description of how a diagram can help you solve 2×40

nasty-shy [4]

Let me explain like this .Suppose There are 40 people gathered somewhere for attending an event.Each Person has to be given 2 sweets for their arrival or for showing their presence in the event. Now 40 other woman joined them..Instead of getting two sweets each of them got one sweet.

Solution: 2 sweets × 40 people = 1 sweet × 80 people = 80

2nd Way:

There are 40 rooms in a building.In Each room we have to fix two bulbs. So How many bulbs are there in the building.

Solution →→→2 bulbs × 40 room = 80 bulbs

Diagram is depicted below for two parts.

4 0

3 years ago

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Brainliest goes to the first CORRECT answer thanks

UNO [17]

Answer:

96 cm^2

Step-by-step explanation:

The triangle can be split into 2 6-8-10 triangles, each with area 24. The bottom parallelogram area is base times height, or 8 * 6, so 48. 24 + 24 + 48 is 96.

8 0

3 years ago

The paper feed on a copying machine has room for a stack of paper 4.0 cm high. If 10 sheets of paper are 0.08 cm thick, how many

Vladimir [108]

I believe it’s 0.4cm ...

5 0

2 years ago

Question 15

Hoochie [10]

Answer:

10% chance or 1/10

Step-by-step explanation:

5 out of the 100 cards are free lunches simplified it would be

1/10

8 0

3 years ago

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Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz

Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The vertical component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the horizontal.

By resolving Jason's force of pull in the horizontal direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11