Question

What is the equation of the circle with center (4, 4) that passes through the point (10, 14)?

Answer 1

Answer:

The answer to your question is      (x - 4)² + (y - 4)² = 136

Step-by-step explanation:

Data

C (4, 4)

P (10, 14)

Process

1.- Calculate the distance from the center to the point

dCP = $\sqrt{(10 - 4)^{2} + (14 - 4)^{2}}$

dCP = $\sqrt{6^{2} + 10^{2}}$

dCP = $\sqrt{36 + 100}$

dCP = $\sqrt{136}$

2.- Calculate the equation of the circle

     ( x - 4)² + (y - 4)² = ($\sqrt{136}$)²

     (x - 4)² + (y - 4)² = 136

Answer 2

Answer:

(x - 4)² + (y - 4)² = 136 is the answer.