Answer: Choice D) x can be anything but 13
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Explanation:
The domain of 
is the same as the domain of g(x)
The domain for g(x) is 
saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because
and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.
That is 100 choices for the first number
99 for the 2nd number
98 for the 3rd number
in total, there are 100*99*98 or 970200 possible combos of winning numbers
Unfortunately, I can't do it on a graph here, but I will do it algebraically.
The solution on the graph will be the point of intersection of the two lines representing the equations.
y + 2.3 = 0.45x . . . . . (1)
-2y = 4.2x - 7.8 . . . . . (2)
From (2), y = 3.9 - 2.1x
substituting for y in (1), we have:
3.9 - 2.1x + 2.3 = 0.45x
2.55x = 6.2
x = 6.2/2.55 = 2.4
y = 3.9 - 2.1(2.4) = 3.9 - 5.04 = -1.2
Therefore, solution is (2.4, -1.2)
He started with 42 cards.
27-6= 21
21×2= 42.
Hope this helps! :)
\(^ ◇^)/
<u>Answer:</u>
Planet A is inner
Planet A is Mars
Planet B is Outer
Planet B is Uranus
<u>Solution:</u>
We know that the inner planets are the planets which are close to the sun. They are relatively small, mostly rocky composition, and have few or no moons.
On other hand, the outer planets are the planets which are far away from the sun. They are mostly huge, ringed, gaseous and have several moons.
In the given problem,
Planet A has rocky mantle and iron core, less no of Moons and no rings, also due to 96% of carbon dioxide, 3% nitrogen and 1% other gases this is denser, and Hence Planet A is inner planet. As the distance from the sun is 1.5 AU and no of moons are 2, hence Planet A is Mars.
On the other hand, Planet B is gaseous with hydrogen and helium gas, hence it is also denser and it has large no of moons and faint rings. So Planet B is Outer planet. As the distance of the planet is 19.22 AU and has 27 moons, hence Planet B is Uranus.
