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xenn [34]
3 years ago
12

Please help me, thank you!!

Mathematics
1 answer:
Aneli [31]3 years ago
4 0
Okay, the answer for the first problem is -24x-54. The second is -12k^4-16k^3+20k^2. Finally. the third one is -24x^3. Hope you get it.
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Please answer i'm not sure
tino4ka555 [31]
It's low ! Hope this helps:3
7 0
3 years ago
Read 2 more answers
Twice the sum of the number and 10 is 60 what is the number?​
n200080 [17]

Let the number be n

\\ \sf\longmapsto 2(n+10)=60

\\ \sf\longmapsto n+10=60/2

\\ \sf\longmapsto n+10=30

\\ \sf\longmapsto n=30-10

\\ \sf\longmapsto n=20

5 0
3 years ago
Instructions: Find the missing side. Round your answer to the nearest
ch4aika [34]

Answer:

Step-by-step explanation:

Tan(51) = opposite / adjacent

The adjacent side makes up the reference angle (51o)

The opposite side is not part of the reference angle

adjacent side = x

opposite side = 16

Tan(51) = 16 / x              Multiply both sides by x

x * Tan(51) = 16            Divide by tan 51

x = 16 / tan(51)

tan(51) = 1.2349

x = 16 / 1.2349

x = 12.96

7 0
2 years ago
4. = 38 -8(n-1), n=1, 2, 3...
stepladder [879]

Answer:

38-8\left(n-1\right),\:n=123:\quad -938

\mathrm{For}\:38-8\left(n-1\right)\:\mathrm{substitute}\:n\space\mathrm{\:with\:}\space123

38-8(123-1)= -938

-938

Step-by-step explanation:

5 0
2 years ago
Help me I don’t get this
andre [41]

Step-by-step explanation:

Area = 8 × 5

Area = 40^2

Perimeter is the length around the edges

Therefore it is 8+8+5×5 (since there are 4 edges)

Perimeter = 2×8 + 2×5

= 40 + 10

= 50cm

4 0
3 years ago
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