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Dmitriy789 [7]
3 years ago
15

How do I solve Y(j(x)) when Y(x)=6x^1/3 and j(x)=3x^-2 Please help

Mathematics
2 answers:
professor190 [17]3 years ago
7 0
You replace j(X) with x in the equation Y(x)

the answer can be:

Y(j(x))= 6(^3rad(0.11x^-2))
Margarita [4]3 years ago
3 0
This is a function composition which means you are putting one function into other.
y(j(x))
y(3x^-2) =
6(3x^-2)^(1/3) =
6(3x)^(-2/3) =
6/ ((3x)^(2/3))
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6/10 is equivalent to 60/100.
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So, 6/10 + 1/50 = 62/100
6/10 + 2/100 = 62/100

(Use 1/50 because that’s the simplified answer!)

I hope this made sense! Good luck!
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