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Dmitriy789 [7]
3 years ago
15

How do I solve Y(j(x)) when Y(x)=6x^1/3 and j(x)=3x^-2 Please help

Mathematics
2 answers:
professor190 [17]3 years ago
7 0
You replace j(X) with x in the equation Y(x)

the answer can be:

Y(j(x))= 6(^3rad(0.11x^-2))
Margarita [4]3 years ago
3 0
This is a function composition which means you are putting one function into other.
y(j(x))
y(3x^-2) =
6(3x^-2)^(1/3) =
6(3x)^(-2/3) =
6/ ((3x)^(2/3))
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The distribution of the probability of the given data is a Positive Skewed Probability distribution.

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<h3>What is a Probability distribution?</h3>

It is a type of distribution in which the distribution has a constant probability, therefore, the probability of each event occurring is equal.

<h3>What is symmetric distribution?</h3>

Symmetric distribution is the type of distribution where the left side of the distribution and the right side of the distribution are mirror images to each other, therefore, they are symmetrical.

<h3>What is Negatively Skewed Probability distribution?</h3>

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<h3>What is Positive Skewed Probability distribution?</h3>

Positive Skewed Probability distribution is a type of distribution of the probability where the left side of the distribution is more concentrated than the right side.

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Learn more about Probability Distribution:

brainly.com/question/795909

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