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3 years ago

How do I solve Y(j(x)) when Y(x)=6x^1/3 and j(x)=3x^-2 Please help

Mathematics

2 answers:

professor190 [17]3 years ago

7 0

You replace j(X) with x in the equation Y(x)

the answer can be:

Y(j(x))= 6(^3rad(0.11x^-2))

Margarita [4]3 years ago

3 0

This is a function composition which means you are putting one function into other.
y(j(x))
y(3x^-2) =
6(3x^-2)^(1/3) =
6(3x)^(-2/3) =
6/ ((3x)^(2/3))

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Two boys on bicycles, 45 miles apart, began racing directly toward each other. The instant they started, a fly on the handle bar

BlackZzzverrR [31]

Complete question is: Each bicycle have speed 10 mi/h and fly flies at 21 mi/h. How far the fly flies?

Answer:

47.25 mi

Step-by-step explanation:

The relative velocity of the bicycles is 10+10 = 20 mi/h

Time in which the two bicycles meet:

$t=\frac{45}{20} = 2.25 h$

Distance covered by fly:

$d=vt\\d=21mi/h\times 2.25h \\d=47.25 mi$

3 0

3 years ago

Solve each proportion

mamaluj [8]

Hello.

In order to solve a proportion, you should cross-multiply:

$\displaystyle\frac{7}{x} =\frac{5}{9}$

Multiply 7 times 9 and 5 times x:

5x=63

Divide both sides by 5:

x= $\displaystyle\frac{63}{5}$

Now let's solve the second proportion.

Multiply 8p times 6 and 12 times 15:

48p=180

Divide both sides by 48:

p=3.75

I hope it helps.

Have an outstanding day.

$\boxed{imperturbability}$

5 0

2 years ago

A wave with a frequency of 60 hertz would generate 60 wave crests every

V125BC [204]

Answer is every second

5 0

3 years ago

What does "n" equal in N+2n+20-4=12+3n?

stira [4]

N+2n+20-4=12+3n
3n+20-4-12=12-12+3n
3n+4=3n
3n/3 + 4= 3n/3
n+4=n
n+4-4=n-4
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theres no further simplification, unless i messed up ...

8 0

3 years ago

The world's population has grown at an average rate of 1.9 percent per year since 1945. There were approximately 4 billion peopl

kkurt [141]

Answer: $f(t) = 4000000000( 1 .019)^t$

Step-by-step explanation:

Here, According to the question, The population of the world is 4 billion (approx).

Again According to the question, The world's population has grown at an average rate of 1.9 percent per year since 1945.

Therefore, after 1975 the growth rate will remains same.

Thus, the population of the world after t years,

$f(t) = 4000000000( 1+\frac{1.9}{100} )^t$ (By the formula $A = P(1+\frac{r}{100})^t$ )

⇒ $f(t) = 4000000000( 1.019 )^t$

Where 1.019 is the growth rate and 4 billion is the initial population.

6 0

3 years ago