Question

How do I solve Y(j(x)) when Y(x)=6x^1/3 and j(x)=3x^-2 Please help

Answer 1

You replace j(X) with x in the equation Y(x)

the answer can be:

Y(j(x))= 6(^3rad(0.11x^-2))

Answer 2

This is a function composition which means you are putting one function into other.
y(j(x))
y(3x^-2) =
6(3x^-2)^(1/3) =
6(3x)^(-2/3) =
6/ ((3x)^(2/3))