How do I solve Y(j(x)) when Y(x)=6x^1/3 and j(x)=3x^-2 Please help

Mathematics

2 answers:

professor190 [17]2 years ago

7 0

You replace j(X) with x in the equation Y(x)

the answer can be:

Y(j(x))= 6(^3rad(0.11x^-2))

Margarita [4]2 years ago

3 0

This is a function composition which means you are putting one function into other.
y(j(x))
y(3x^-2) =
6(3x^-2)^(1/3) =
6(3x)^(-2/3) =
6/ ((3x)^(2/3))

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