Answer:
Technology is the sum of techniques, skills, methods, and processes used in the production of goods or services or in the accomplishment of objectives, such as scientific ... computer. As a cultural activity, technology predates both science and engineering, each of which formalize some aspects of technological endeavor.
Explanation:
Answer:
d= 1400 ft :Distance from the starting point where the car reaches the truck
Explanation:
Car Kinematics : the car has uniformly accelerated movement, so we apply the following equation for distance
d₁= v₀₁*t + (1/2)* a₁*t₁² Equation 1
d₁: car distance (ft)
v₀₁: car initial speed (ft/s)
a₁ : car acceleration (ft/s²)
t1 : car time (s)
Truck Kinematics: The truck moves with uniform motion (constant speed), so the equation for distance is:
d₂= v₂*t₂ Equation (2)
d₂: truck distance (ft)
v₂: truck speed (ft/s)
t₂ : truck time (s)
Known data
v₀₁ = 0
a₁ = 7 ft/s²
v₂ = 70 ft/s
Problem development
The time and distance for when the car catches the truck is the same, then:
d₁=d₂ and t₁=t₂= t
Equation (1 )= the Equation ( 2)
v₀₁*t₁ + (1/2)* a₁*t₁² = v₂*t₂
v₀₁*t + (1/2)* a₁*t²= v₂*t
0*t + (1/2)*7*t² = 70*t : we divide both sides of the equation by t
(1/2)*7*t = 70
t= 20 s
We replace t= 20 s in the equation (2)
d= 70*20 = 1400 ft :Distance from the starting point where the car reaches the truck
Answer:
Chemical weathering
Explanation:
This changes the molecular structure of rocks and soil. For instance, carbon dioxide from the air or soil sometimes combines with water in a process called carbonation. This produces a weak acid, called carbonic acid, that can dissolve rock.
Answer: Lightning is mostly light and electricity, this light that is hitting is going at a rate of 299,792.458 km per second (or 186,282 miles per second) this is so much compared to sound which only travels at about 761 mph (or approximately 332 meters per second). Fun fact: The lightening you are seeing is that coming back to the cloud because the process happens so fast.
Explanation:
Answer:
1.dr/dt=0.0096cm/s
2. dA/dt=2.19cm^2/s
Explanation:
A spherical balloon is deflating at 10 cm3/s. At what rate is the radius changing when the volume is 1000π cm3 ? What is the rate of change of surface area at this moment?
for this question, we need to analyze the parameters we know
V=volume of the spherical balloon 1000π cm3
volume of the sphere=
1000π=4/3πr^3
dividing both sides by 4
250*3=r^3
r=9.08cm, the radius of the balloon
dv/dt=dv/dr*dr/dt...................................1
dv/dr ,means
V=
dv/dr=4*pi*r^2
dv/dt=10 cm3/s
from equ 1
10=4*pi*9.08^2*dr/dt
10=1036 dr/dt
dr/dt=10/1036
dr/dt=0.0096cm/s
2. to find the rate at which the area is changing we have,
dA/dt=dA/dr*dr/dt
area of a sphere is 4πr^2
differentiate a with respect to r, radius
dA/dr=8πr
dA/dt=8πr*0.0096
dA/dt=8*pi*9.08*0.0096
dA/dt=2.19cm^2/s
is the rate of change of the surface area